MRJob - Python - 当除法为0 /值时如何返回null

Question

如何修改此代码，以便当senti_avg不可分（0 /值）时，reducer（）输出NULL或NONE而不是崩溃？

def reducer(self, bs_id, value):
    avg_data = list(value)
    senti_sum = sum([a[0] for a in avg_data])
    word_sum = sum([a[1] for a in avg_data])
    senti_avg = senti_sum/float(word_sum)

    yield (bs_id, senti_avg)

Answer 1

您使用python exception handling：

try:
    senti_avg = senti_sum/float(word_sum)
except ZeroDivisionError:
    senti_avg = None