UNIX日期的操作

时间:2013-04-09 08:22:01

标签: php mysql unix date format

我正在制作这样的SQL:

SELECT * FROM POST
WHERE date between :date1 and :date2

Date2始终是今天的日期PHP time(); (UNIX格式)。 现在我需要将date2减去7days(1周)和date2减去1个月。

(这将由用户在表单上选择。)

问题是我无法使用UNIX日期工作。

$date2 = time();
$date1 = $_GET['fromDate'];

$query = "SELECT * FROM POST
          WHERE date between :date1 and :date2";

HTML表格

 select id=fromDate>
    <option value=<?php echo time()-604800>WEEK</option>
/select>

2 个答案:

答案 0 :(得分:1)

$today = time();
$oneWeekAgo = time() - (60 * 60 * 24 * 7); // 60 seconds, 60 minutes, 24 hours, 7 days
$oneMonthAgo = time() - (60 * 60 * 24 * 30); // 60 seconds, 60 minutes, 24 hours, 30 days

或更准确的是$ oneMonthAgo:

$date = date_create(); // get DateTime object of today
date_modify($date, "-1 month"); // 1 month ago
$oneMonthAgo = date_timestamp_get($date); // get unix time

答案 1 :(得分:0)

你尝试了什么?

$t=time();
# this would output current date
echo(date("D F d Y",$t));
# minus 7 days converted to seconds
$t -= 7*24*60*60;
# this would print the original $t minus 7 days
echo(date("D F d Y",$t));