Question

与我之前提出的问题相关：how to insert subtract of each two subsequent rows and inserting it into a new column

我有另一个问题。在下表中;我想计算每个用户上次参加比赛的时间。事实上，我应该从当前日期减去最后一个获胜日期。（地方= 1）表示获胜。

当前表：

http://www.8pic.ir/images/75206897877200828586.jpg

我想要的结果：

http://www.8pic.ir/images/78832309907063712878.jpg

我为这个问题写了以下查询（根据我之前的问题here给出的答案）！但问题是我得到了很多重复的行！我只有4000行，但是当我运行这个查询时，我得到40,000行！问题是什么！你能帮我吗？而且我对以前没有赢过的用户也有负面价值。我希望这些字段为NULL。

;WITH [cte15853354] AS
 (
    SELECT 
        [user-name],
        [submissions],
        [date],
        [place],
        [recency],
        ROW_NUMBER() OVER (ORDER BY [user-name], [date] DESC) AS [ROWNUMBER]
    FROM dbo.[top-design1]
 )
SELECT 
    t.[user-name],
    t.[submissions],
    t.[date],
    t.[place],
    t.[recency],
    DATEDIFF(DAY, ISNULL(k.[date],t.[date]),t.[date]) AS [win-recency]
INTO dbo.[top-design2]
FROM [cte15853354] t
LEFT JOIN [cte15853354] k
    ON k.[user-name] = t.[user-name] 
     where k.[place]=1 
    ORDER BY t.[user-name], t.[date] DESC

Answer 1

你去了（实际上不需要进行案例测试）：

SELECT [user-name], 
       submissions,
       [date],
       place,
       recency,
       DATEDIFF(DAY, 
       (SELECT TOP(1) [date]
        FROM [top-design1] td1
        WHERE td1.[user-name] = [top-design1].[user-name]
        AND place = 1
        AND [date] < [top-design1].[date]
        ORDER BY [date] DESC), [date]) as recencywin
FROM [top-design1]

我认为您可以自行管理将其用于插入目的。

减去两行的值并将其插入新列（不是后续行）

1 个答案: