使两个脚本一起工作以获得下拉菜单

时间:2013-04-08 22:52:53

标签: javascript css

我有这个HTML代码

<html>
<head>
<script type="text/javascript">
    window.onload = function(){
    document.getElementById("shipping-method").onchange = function(){
        window.scrollTo(0, 0);
    };
};
</script>
<script>
function calc() {
var subtotal = parseFloat(document.getElementById("subtotal").innerHTML.substring(1));
var shipping = parseInt(document.getElementById("shipping-method").value);
if(shipping == 1) {
    var total = subtotal+6.95;
    document.getElementById("shipping").innerHTML = "$"+6.95;
} else {
    var total = subtotal+17.95;
    document.getElementById("shipping").innerHTML = "$"+17.95;
}
document.getElementById("total").innerHTML = "$"+total;
}
</script>
</head>
<body>
<select  onchange="calc()" class="shipping-method" id="shipping-method">
<option value="">-Choose a shipping method-</option>
<option selected="selected" value="1">normal shipping - $6.95</option>
<option value="2">Priority Shipping - $17.95</option>

</select>
<div class="calculations">
<table>

<tbody><tr>
    <td>Subtotal:</td>
    <td id="subtotal">$97.00</td>
</tr>


<tr>
    <td>Shipping:</td>
    <td id="shipping">$6.95</td>
</tr>



<tr class="total">
    <td>Total:</td>
    <td id="total">$103.95</td>
</tr>
</tbody></table>
</div>
</body>
</html>

下拉菜单位于网页的底部,因此我选择其中一个选项并获取总数后,使用第一个脚本将用户置于页面顶部,但两个脚本不能同时工作,我必须删除其中一个让另一个工作,如何让两个脚本一起工作而没有任何冲突,谢谢。

2 个答案:

答案 0 :(得分:1)

尝试坚持下去:

function calc() {
var subtotal = parseFloat(document.getElementById("subtotal").innerHTML.substring(1));
var shipping = parseInt(document.getElementById("shipping-method").value);
if(shipping == 1) {
    var total = subtotal+6.95;
    document.getElementById("shipping").innerHTML = "$"+6.95;
} else {
    var total = subtotal+17.95;
    document.getElementById("shipping").innerHTML = "$"+17.95;
}
document.getElementById("total").innerHTML = "$"+total;
}

就在顶部的功能之前:

window.onload = function(){
document.getElementById("shipping-method").onchange = function(){
    window.scrollTo(0, 0);
};

答案 1 :(得分:1)

您正在覆盖onchange功能。如果你想做两件事,那么把它们放在onchange函数中,不要分配两次。

以下是一些示例代码(简称简称)。

<html>
<head><title>Example</title></head>
<body>
<select id="shipping-method"></select>
<table></table>
<script type="text/javascript">
    function calc() {
        // do calculations here
    }
    document.getElementById("shipping-method").onchange = function(){
        window.scrollTo(0, 0); // scroll to top
        calc(); // call function
    };
</script>
</body>
</html>

请注意,我将javascript放在底部以避免访问不存在的元素。