我正在学习AWK并正在尝试内置字符串函数的练习。
这是我的练习:
我的文件包含如下
RecordType:83
1,2,3,a|x|y|z,4,5
我想要的输出如下:
RecordType:83
1,2,3,a,4,5
1,0,0,x,4,5
1,0,0,y,4,5
1,0,0,z,4,5
我为上面的输出写了一个awk命令。
awk -F',' '$1 ~ /RecordType:83/{print $0}
$1 == 1{
split($4,splt,"|")
for(i in splt)
{
if(i==1)
print $1,$2,$3,splt[i],$5,$6
else
print $1,0,0,splt[i],$5,$6
}
}' OFS=, file_name
上面的命令看起来很笨拙。有没有办法最小化命令?
提前致谢
答案 0 :(得分:3)
我可以管理的最短单线:
awk -F, 'NR>1{n=split($4,a,"|");for(;i++<n;){$4=a[i];print;$2=$3=0}}NR==1' OFS=, file
RecordType:83
1,2,3,a,4,5
1,0,0,x,4,5
1,0,0,y,4,5
1,0,0,z,4,5
更易阅读的脚本(推荐):
BEGIN {
FS=OFS="," # Comma delimiter
}
NR==1 { # If the first line in file
print $0 # Print the whole line
next # Skip to next line
}
{
n=split($4,a,"|") # Split field four on |
for(i=1;i<=n;i++) # For each sub-field
print $1,i==1?$2OFS$3:"0"OFS"0",a[i],$5,$6 # Print the output
}
答案 1 :(得分:1)
另一个较短的单行
awk -F, -v OFS="," 'NR>1{n=split($4,a,"|");while(++i<=n){$4=a[i];print;$2=$3=0}}NR==1' file
以你的例子:
kent$ awk -F, -v OFS="," 'NR>1{n=split($4,a,"|");while(++i<=n){$4=a[i];print;$2=$3=0}}NR==1' file
RecordType:83
1,2,3,a,4,5
1,0,0,x,4,5
1,0,0,y,4,5
1,0,0,z,4,5