我有这个代码（如下所示）和变量$ first_name = $ _ POST ['first_name'];似乎不起作用。我有用户名，密码和标题工作。是否与使用下划线有关？我检查过它与数据库匹配。当用户创建一个帐户时，存储first_name的行会引发错误，并且不会显示在数据库中输入的名称。有什么想法吗？
<?php
/* This code will make a connection with database */
$con=mysql_connect("localhost","","");
/* Now, we select the database */
mysql_select_db("");
/* Now we will store the values submitted by form in variable */
$username=$_POST['username'];
$pass=$_POST['password'];
$title=$_POST['title'];
$first_name=$_POST['first_name'];
/* we are now encrypting password while using md5() function */
$password=md5($pass);
$confirm_password=$_POST['confirm_password'];
/* Now we will check if username is already in use or not */
$queryuser=mysql_query("SELECT * FROM Customer WHERE username='$username' ");
$checkuser=mysql_num_rows($queryuser);
if($checkuser != 0)
{ echo "Sorry, ".$username." is already been taken."; }
else {
/* now we will check if password and confirm password matched */
if($pass != $confirm_password)
{ echo "Password and confirm password fields were not matched"; }
else {
/* Now we will write a query to insert user details into database */
$insert_user=mysql_query("INSERT INTO Customer (username, password, title, first_name) VALUES ('$username', '$password', '$title', '$first_name')");
if($insert_user)
{ echo "Registration Succesfull"; }
else
{ echo "error in registration".mysql_error(); }
/* closing the if else statements */
}}
mysql_close($con);
?>
谢谢！
HTML表单
<!DOCTYPE html>
<html>
<head>
<meta charset="utf-8" />
<meta name="viewport" content="width=device-width, initial-scale=1" />
<meta name="apple-mobile-web-app-capable" content="yes" />
<meta name="apple-mobile-web-app-status-bar-style" content="black" />
<title>
</title>
<link rel="stylesheet" href="https://ajax.aspnetcdn.com/ajax/jquery.mobile/1.2.0/jquery.mobile-1.2.0.min.css" />
<link rel="stylesheet" href="my.css" />
<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.7.2/jquery.min.js">
</script>
<script src="https://ajax.aspnetcdn.com/ajax/jquery.mobile/1.2.0/jquery.mobile-1.2.0.min.js">
</script>
<script src="my.js">
</script>
<!-- User-generated css -->
<style>
</style>
<!-- User-generated js -->
<script>
try {
$(function() {
});
} catch (error) {
console.error("Your javascript has an error: " + error);
}
</script>
</head>
<body>
<!-- Home -->
<div data-role="page" id="page1">
<div data-theme="a" data-role="header">
<a data-role="button" data-theme="d" href="Login.html" data-icon="arrow-l" data-iconpos="left" class="ui-btn-left">
Back
</a>
<a data-role="button" href="index.html" data-icon="home" data-iconpos="right" data-theme="d"class="ui-btn-right">
Home
</a>
<h3>
Registration
</h3>
</div>
<div data-role="content">
<h4>
Enter your details below to register:
</h4>
<form method="post" action="Login.php">
<table border="0">
<tr><td>Title: </td><td><input type="text" name="title" /></td></tr>
<tr><td>First Name: </td><td><input type="text" name="name" /></td></tr>
<tr><td>Username: </td><td><input type="text" name="username" /></td></tr>
<tr><td>Password: </td><td><input type="password" name="password" /></td></tr>
<tr><td>Confirm Password: </td><td><input type="password" name="confirm_password" /></td></tr>
<tr><td></td><td><input type="submit" value="submit" /></td></tr>
</table>
</form>
<div data-role="content">
<h4>
Please ensure your username and password are kept secure.
</h4>
<br />
</div>
</div>
</body>
</html>
答案 0 :(得分：3)
问题是first name的输入文字的表单属性为name而不是first_name。所以你应该改变
$first_name=$_POST['first_name'];
到
$first_name=$_POST['name'];
或将您的名称属性更改为first_name
在插入
之前，还要对所有字段进行适当的转义<?php
/* This code will make a connection with database */
$con=mysql_connect("localhost","","");
/* Now, we select the database */
mysql_select_db("");
/* Now we will store the values submitted by form in variable */
$username= mysql_real_escape_string($_POST['username']);
$pass= mysql_real_escape_string($_POST['password']);
$title= mysql_real_escape_string($_POST['title']);
$first_name= mysql_real_escape_string($_POST['name']);
/* we are now encrypting password while using md5() function */
$password= md5($pass);
$confirm_password= mysql_real_escape_string($_POST['confirm_password']);
/* Now we will check if username is already in use or not */
$queryuser=mysql_query("SELECT * FROM Customer WHERE username='$username' ");
$checkuser=mysql_num_rows($queryuser);
if($checkuser != 0)
{ echo "Sorry, ".$username." is already been taken."; }
else {
/* now we will check if password and confirm password matched */
if($pass != $confirm_password)
{ echo "Password and confirm password fields were not matched"; }
else {
/* Now we will write a query to insert user details into database */
$insert_user=mysql_query("INSERT INTO Customer (username, password, title, first_name) VALUES ('$username', '$password', '$title', '$first_name')");
if($insert_user)
{ echo "Registration Succesfull"; }
else
{ echo "error in registration".mysql_error(); }
/* closing the if else statements */
}}
mysql_close($con);
?>
答案 1 :(得分：0)
改变它：
$first_name = mysql_real_escape_string($_POST['first_name']);
您目前正在保存而没有任何消毒或逃避。
答案 2 :(得分：0)
改变这个：
$insert_user=mysql_query("INSERT INTO Customer (username, password, title, first_name) VALUES ('$username', '$password', '$title', '$first_name')");
对此：
$insert_user=mysql_query("INSERT INTO Customer (username, password, title, first_name) VALUES ('".$username."', '".$password."', '".$title."', '".$first_name."')");
<强>更新
请检查<input type="text" name="first_name">是否有name="first_name"
答案 3 :(得分：0)
好吧，看起来您的表单不包含first_name项，而是name。将其更改回first_name