如何使用session / function或javascript将变量从插件php传递到wordpress中的另一个php文件?

时间:2013-04-08 08:40:10

标签: php wordpress plugins wordpress-plugin

我有oneplugin文件testplugin.php..它包含变量$ abc;

// main plugin.php

if(!is_admin()){
new Funtion_Button();
}
class Function_Button
{

if(is_single() || is_page() || is_home() ){  
      global $post; 
      global $wpdb; 

 $query_images_args = array(
     'post_type' => 'attachment' , 'post_mime_type' =>'image','post_status' => 'published', 'posts_per_page' => -1,'numberposts' => 1

$query_images = new WP_Query( $query_images_args );
         $images = array();
         foreach ( $query_images->posts as $image) {
         $images[]= wp_get_attachment_url( $image->ID );

         }
                 $abc[]=0;
         $abc= $abc.http_build_query($images);
                 $_SESSION['arrayImg']=$abc;
 );
}

///接收文件

include ('testplugin.php'); 
session_start();
$array1[]=$abc;

现在这个$ abc来自主插件页面

但是我收到了这个错误

致命错误:在第98行的C:\ wamp \ www \ wordpress \ wp-content \ plugins \ testplugin.php中调用未定义的函数is_admin()

在98行,我有 if(!is_admin()){

1 个答案:

答案 0 :(得分:1)

使用会话:

//在testplugin.php上

session_start();
$_SESSION['varname'] = $var_value;

//在另一个档案

session_start();
$var_value = $_SESSION['varname'];

使用cookies:

//在testplugin.php上

$_COOKIE['varname'] = $var_value;

//第2页

$var_value = $_COOKIE['varname'];