Question

我正在比较两个日期From_date＆amp; To_date与我的数据库表行。

逻辑是：如果用户已经在这两个日期（从文本框中收到的日期）之间设置了预算，则会返回错误消息Budget already set for this from-date & to-date。

我将日期转换为Unix时间戳更容易。

在尝试此操作之前，我会参考此链接： 1. how to check two dates between from-date and to-date 2。 What's the most efficient way to test two integer ranges for overlap?

我尝试了以下代码：但我没有得到结果。它总是向我显示错误消息即 Budget already set for this from-date & to-date

 <?php  if (isset($_POST['submit']))
        {
             include '../../../include/connection.php'; 
             $frmdate= $_POST['frmdate'] ;
             $todate=$_POST['todate'] ; 
             $fromTimestamp = strtotime( $frmdate );
              $toTimestamp = strtotime( $todate ); 

     function  check_function($fromTimestamp,$toTimestamp)//function for checking the two dates which are rrecieved from the database table
           {
             $sid=$_SESSION['id'];
             $result12=mysql_query("SELECT * FROM budget where creater_id = '$sid'"); 
             while($test12 = mysql_fetch_array($result12))
                 {
                   $from_date = strtotime($test12['from_date']);//getting all the FROM-Dates_column
                   $to_date = strtotime($test12['to_date']);//getting all the TO-Dates_column

                    if((($fromTimestamp >= $from_date) && ($fromTimestamp <= $to_date)) || (($toTimestamp >= $from_date) && ($toTimestamp <= $to_date)))
                       {
                         return TRUE;
                         break;
                       }
                    return FALSE;
                  }
            }

           if(check_function($fromTimestamp,$toTimestamp))//Returns TRUE
              {
                  mysql_query("INSERT INTO `budget` (heads_id,amount,from_date,to_date,creater_id,created_date,updater_id,updated_date) VALUES ('$headsid','$amount','$frmdate','$todate',$uid,NOW(),$uid,NOW())");
              }
            else
              {
                 echo 'Budget already set for this from-date & to-date';   //
             }
        }  ?>

Answer 1

试试这个..

if(isset($to_date) && isset($from_date)){
    if((($fromTimestamp >= $from_date) && ($fromTimestamp <= $to_date)) || (($toTimestamp >= $from_date) && ($toTimestamp <= $to_date)))
    {
      $val = 'Y'; //return Y in meet this condition
    }
    else{
      $val = 'N'; // return N if meet this condition
    }
}
if($val == 'Y') //Returns TRUE
{
mysql_query("INSERT INTO `budget` (heads_id,amount,from_date,to_date,creater_id,created_date,updater_id,updated_date) VALUES ('$headsid','$amount','$frmdate','$todate',$uid,NOW(),$uid,NOW())");
}
else
{
echo 'Budget already set for this from-date & to-date';   //
}

Answer 2

您是否尝试使用默认的mysql日期格式2013/04/11进行比较（年/月/日）??如果您只考虑约会，那么您必须存储您的具有Y / m / d格式的mysql数据库中的数据也可以与之比较一样！它效果最好（y）

1）以MySQL日期格式存储：

date("Y/m/d", strtotime($Date));

2）比较日期

<?php  
if (isset($_POST['submit']))
{
    include '../../../include/connection.php'; 
    $frmdate=  date("Y/m/d", strtotime($_POST['frmdate']));
    $todate= date("Y/m/d", strtotime($_POST['todate'])); 
     .. so on
}
?>

Answer 3

我刚看了你的代码。

你的while循环往往只运行一次。返回FALSE; statement是while循环中的最后一个语句。因此，如果您查询返回多个结果，循环似乎意味着，您将始终只获取一个结果。在该运行之后，您的函数返回true（当第一个结果与if语句匹配时）或者在任何其他情况下返回false。

while($test12 = mysql_fetch_array($result12))
{
   $from_date = strtotime($test12['from_date']);//getting all the FROM-Dates_column
   $to_date = strtotime($test12['to_date']);//getting all the TO-Dates_column

   if((($fromTimestamp >= $from_date) && ($fromTimestamp <= $to_date)) || (($toTimestamp >= $from_date) && ($toTimestamp <= $to_date)))
   {
     return TRUE;
     break;
   }
   return FALSE;
}

关于两个陈述的最后说明

return TRUE;
break;

此处不需要中断，返回已经突破了while循环。

希望这能解决你的问题！

Answer 4

function  check_function($fromTimestamp,$toTimestamp)//function for checking the two dates which are rrecieved from the database table
 {
 $sid=$_SESSION['id'];
$result12=mysql_query("SELECT * FROM budget where creater_id = '$sid' and from_date >= $frmdate and to_date <= $todate")
if(mysql_num_rows($result12) > 0)
{
return true;
}
else
{
return false;
}
}


if(check_function($fromTimestamp,$toTimestamp)==TRUE)//Returns TRUE
              {
                  mysql_query("INSERT INTO `budget` (heads_id,amount,from_date,to_date,creater_id,created_date,updater_id,updated_date) VALUES ('$headsid','$amount','$frmdate','$todate',$uid,NOW(),$uid,NOW())");
              }
            else
              {
                 echo 'Budget already set for this from-date & to-date';   //
             }

Answer 5

html格式的格式是什么？ $ frmdate = $ _POST ['frmdate']; $ todate = $ _ POST ['todate'];

你的列表中的格式是什么？例如：DATE，VARCHAR，TIMESTAMP等......

PHP：无法比较两个日期结果

5 个答案: