我正在使用JSONParser.makeHttpRequest
发布一些数据。当连接速度很慢时,需要一段时间才能得到响应,我想将超时限制设置为5秒。我发现this post显示了如何设置HttpResponse超时但无法将其与JSONParser集成。
这是我用于HttpRequest的代码
JSONParser jParser = new JSONParser();
List<NameValuePair> params = new ArrayList<NameValuePair>();
JSONObject json = jParser.makeHttpRequest(url, "GET", params);
如果我能在其他地方获得代码片段或其他帖子的链接,我将不胜感激。
答案 0 :(得分:2)
以下是代码:
public class JSONParser {
static InputStream is = null;
static JSONObject jObj = null;
static String json = "";
int timeout;
// constructor
public JSONParser() {
timeout = new Values().gettimeout();
}
// function get json from url
// by making HTTP POST or GET method
public JSONObject makeHttpRequest(String url, String method,
List<NameValuePair> params) {
// Making HTTP request
try {
HttpParams httpParameters = new BasicHttpParams();
HttpConnectionParams.setSoTimeout(httpParameters, timeout);
// check for request method
if(method == "POST"){
// request method is POST
// defaultHttpClient
DefaultHttpClient httpClient = new DefaultHttpClient(httpParameters);
HttpPost httpPost = new HttpPost(url);
httpPost.setEntity(new UrlEncodedFormEntity(params));
HttpResponse httpResponse = httpClient.execute(httpPost);
HttpEntity httpEntity = httpResponse.getEntity();
is = httpEntity.getContent();
}else if(method == "GET"){
// request method is GET
DefaultHttpClient httpClient = new DefaultHttpClient(httpParameters);
String paramString = URLEncodedUtils.format(params, "utf-8");
url += "?" + paramString;
HttpGet httpGet = new HttpGet(url);
HttpResponse httpResponse = httpClient.execute(httpGet);
HttpEntity httpEntity = httpResponse.getEntity();
is = httpEntity.getContent();
}
} catch (UnsupportedEncodingException e) {
e.printStackTrace();
} catch (ClientProtocolException e) {
e.printStackTrace();
} catch (IOException e) {
e.printStackTrace();
}
try {
BufferedReader reader = new BufferedReader(new InputStreamReader(
is, "iso-8859-1"), 8);
StringBuilder sb = new StringBuilder();
String line = null;
while ((line = reader.readLine()) != null) {
sb.append(line + "\n");
}
is.close();
json = sb.toString();
} catch (Exception e) {
Log.e("Buffer Error", "Error converting result " + e.toString());
}
// try parse the string to a JSON object
try {
jObj = new JSONObject(json);
} catch (JSONException e) {
Log.e("JSON Parser", "Error parsing data " + e.toString());
}
// return JSON String
return jObj;
}
}
秘密是:
HttpParams httpParameters = new BasicHttpParams();
HttpConnectionParams.setSoTimeout(httpParameters, timeout);
并在
中设置de HttpParams DefaultHttpClient httpClient = new DefaultHttpClient(httpParameters);
调整你的代码来做到这一点;)
答案 1 :(得分:0)
您可以使用Asynctask,并在一段时间后停止请求。 请参阅示例here。