Question

我在应用程序从yaml描述文件启动时动态生成django模型。我在django admin中注册它们，但它们在管理界面中显示为禁用。看起来像this。

我创建了manage.py命令，以yaml格式从描述文件中动态创建模型。

from django.core.management.base import BaseCommand
from django.core.management import call_command

import yaml

from generation.generate import generate_fields, generate_model


class Command(BaseCommand):
    help = 'Generates or updates django models from specified file'

    def handle(self, *args, **options):
        try:
            f = open(args[0], 'r')
            models = yaml.safe_load(f)
            f.close()
            for name, definition in models.items():
                fields = generate_fields(definition['fields'])
                generate_model(name, definition['title'], fields, "generation", "generation.models")
            call_command('syncdb', interactive=True)
        except IOError:
            self.stderr.write('Cannot open file: {0}'.format(args[0]))
        except yaml.YAMLError as e:
            self.stderr.write('Cannot parse file {0}: {1}'.format(args[0], e))

我从root urls.py启动此命令，如下所示：

from django.conf.urls import patterns, include, url
from django.contrib import admin
from generation import views
from generation.management.commands.updatemodels import Command

admin.autodiscover()

urlpatterns = patterns('',
    url(r'^$', views.main, name='main'),
    # url(r'^modgen/', include('modgen.foo.urls')),

    url(r'^admin/', include(admin.site.urls)),
)

Command().handle('models.yaml')

我以这种方式生成模型并在管理员中注册：

from sys import stderr
from django.contrib import admin
from django.db import models


class Types():
    INT = 'int'
    CHAR = 'char'
    DATE = 'date'


def generate_model(model_name, model_title, fields, app_label, module):
    class Meta:
        pass
    if app_label:
        setattr(Meta, 'app_label', app_label)
    if model_title:
        setattr(Meta, 'verbose_name_plural', model_title)
    attrs = {'__module__': module, 'Meta': Meta}
    if fields is not None:
        attrs = dict(attrs.items() + fields.items())
    model = type(model_name, (models.Model,), attrs)
    admin.site.register(model)


def generate_fields(definition):
    fields = {}
    for field in definition:
        fields[field['id']] = generate_field(field['title'], field['type'])
    return fields


def generate_field(title, field_type):
    if field_type == Types.CHAR:
        return models.CharField(title, max_length=255)
    elif field_type == Types.INT:
        return models.IntegerField(title)
    elif field_type == Types.DATE:
        return models.DateField(title)
    else:
        stderr.write('Unknown field type specified: {0}'.format(field_type))

为什么模型在管理界面中显示为禁用？ Django成功地注册了它们。

Answer 1

可能首先需要编辑（或创建）文件generation/admin.py，然后添加此代码以在django-admin部分注册应用程序模型。

from django.contrib import admin
from myproject.generation.models import Rooms, Users

class RoomsAdmin(admin.ModelAdmin):
    pass


class UsersAdmin(admin.ModelAdmin):
    pass


admin.site.register(Rooms, RoomsAdmin)
admin.site.register(Users, UsersAdmin)

为什么我的模型在django admin中显示为禁用？

1 个答案: