Question

我有一张桌子：

| foo | bar |
+-----+-----+
| a   | abc |
| b   | def |
| c   | ghi |
| d   | jkl |
| a   | mno |
| e   | pqr |
| c   | stu |
| f   | vwx |

我想删除foo列中包含重复项的所有行，以便表格如下所示：

| foo | bar |
+-----+-----+
| b   | def |
| d   | jkl |
| e   | pqr |
| f   | vwx |

最有效的方式是什么？

Answer 1

您可以从子查询加入表，该子查询仅使用foo返回唯一LEFT JOIN。子查询上没有匹配的行将根据需要删除，例如

DELETE  a
FROM    TableName a
        LEFT JOIN
        (
            SELECT  foo
            FROM    TableName
            GROUP   BY Foo
            HAVING  COUNT(*) = 1
        ) b ON a.Foo = b.Foo
WHERE   b.Foo IS NULL

SQLFiddle Demo

为了提高性能，请在列Foo上添加索引。

ALTER TABLE tableName ADD INDEX(foo)

Answer 2

使用EXISTS：

DELETE a
  FROM TableName a
 WHERE EXISTS (SELECT NULL
                 FROM TableName b
                WHERE b.foo = a.foo
             GROUP BY b.foo
               HAVING COUNT(*) > 1)

使用IN：

DELETE a
  FROM TableName a
 WHERE a.foo IN (SELECT b.foo
                   FROM TableName b
               GROUP BY b.foo
                 HAVING COUNT(*) > 1)

从表中删除所有重复行的最有效方法是什么？

2 个答案: