我有2个Spinnery,它有一些价值(在两个微调器中相同)。如何在2个微调器中看不到1个微调器的值?如果您选择1个spinnerze的值,那么她将在第二个中看到。
答案 0 :(得分:0)
package com.stack.question;
import android.app.Activity;
import android.os.Bundle;
import android.view.View;
import android.widget.AdapterView;
import android.widget.AdapterView.OnItemSelectedListener;
import android.widget.ArrayAdapter;
import android.widget.Spinner;
public class StackActivity extends Activity {
Spinner spinner1, spinner2;
/** Called when the activity is first created. */
@Override
public void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.main);
spinner1 = (Spinner) findViewById(R.id.spinner1);
spinner2 = (Spinner) findViewById(R.id.spinner2);
ArrayAdapter<String> adapterType = new ArrayAdapter<String>(this,
android.R.layout.simple_spinner_item, new String[] { "data1",
"data2" });
adapterType
.setDropDownViewResource(android.R.layout.simple_spinner_dropdown_item);
spinner1.setAdapter(adapterType);
spinner2.setAdapter(adapterType);
spinner1.setOnItemSelectedListener(new OnItemSelectedListener() {
@Override
public void onItemSelected(AdapterView<?> arg0, View arg1,
int arg2, long arg3) {
// TODO Auto-generated method stub
ArrayAdapter<String> adapter2 = new ArrayAdapter<String>(
StackActivity.this,
android.R.layout.simple_spinner_item, new String[] {
"roma", "milan" });
adapter2.setDropDownViewResource(android.R.layout.simple_spinner_dropdown_item);
spinner2.setAdapter(adapter2);
}
@Override
public void onNothingSelected(AdapterView<?> arg0) {
// TODO Auto-generated method stub
}
});
}
}
<LinearLayout xmlns:android="http://schemas.android.com/apk/res/android"
android:layout_width="fill_parent"
android:layout_height="fill_parent"
android:orientation="vertical" >
<Spinner
android:id="@+id/spinner1"
android:layout_width="fill_parent"
android:layout_height="wrap_content" />
<Spinner
android:id="@+id/spinner2"
android:layout_width="fill_parent"
android:layout_height="wrap_content" />
</LinearLayout>