我已经设置了弹出窗口,但是我想将它放在按钮(View v)下面,需要点击它才能打开它:
public void showPopup(Context c, View v){
int[] location = new int[2];
v.getLocationOnScreen(location);
ViewGroup base = (ViewGroup) getView().findViewById(R.id.pup_pattern);
LayoutInflater inflater = (LayoutInflater) c.getSystemService(Context.LAYOUT_INFLATER_SERVICE);
View pupLayout = inflater.inflate(R.layout.linearlayout_popup, base);
final PopupWindow pup = new PopupWindow(pupLayout, android.view.ViewGroup.LayoutParams.WRAP_CONTENT, android.view.ViewGroup.LayoutParams.WRAP_CONTENT);
int x = location[0] - (int) ((pupLayout.getWidth() - v.getWidth()) / 2 ); // --> pupLayout.getWidth() gives back -2?
int y = location[1] + v.getHeight() + 10;
pup.setFocusable(true);
pup.showAtLocation(v, Gravity.NO_GRAVITY, x, y);
}
有人有想法获得措施吗?
答案 0 :(得分:27)
您将无法获得未在屏幕上绘制的视图的高度或宽度。
pupLayout.getWidth()
//这会给你0
你需要得到像这样的宽度
int width = MeasureSpec.makeMeasureSpec(0, MeasureSpec. UNSPECIFIED);
像这样使用
View pupLayout = inflater.inflate(R.layout.linearlayout_popup, base);
pupLayout.measure(MeasureSpec.makeMeasureSpec(0, MeasureSpec.UNSPECIFIED),
MeasureSpec.makeMeasureSpec(0, MeasureSpec.UNSPECIFIED));
int x = location[0] - (int) ((pupLayout.getMeasuredWidth() - v.getWidth()) / 2 );
答案 1 :(得分:-1)
另一种方式:
/**
* @return Point object which:<br>
* point.x : contains width<br>
* point.y : contains height
*/
public static Point getViewSize(View view) {
Point size = new Point();
view.post(new Runnable() {
@Override
public void run() {
size.set(view.getWidth(), view.getHeight());
}
});
return size;
}