Question

我收到了这段代码：

..some code here..
<a href="members/username1.12345/" class="username bigs" title="">Username 1</a>
..some code here..
..some code here..
<a href="members/username2.55334/" class="username bigs" title="">Username 2</a>
..some code here..
..some code here..
<a href="members/username3.23455/" class="username bigs" title="">Username 3</a>
..some code here..
..some code here..
<a href="members/username4.45545/" class="username bigs" title="">Username 4</a>
..some code here..

如何使用preg_match_all（）获取用户名1，用户名2，用户名3，用户名4等。

我不想使用SimpleHTMLdom或其他..我想用preg_match_all（）来做..怎么做？我试过很多正则表达式......但是没有一个正常工作..

Answer 1

Regexp是个糟糕的主意。但仍然 - 试试这个：@<a href="members/.+/" class="username bigs" title="">(.+)</a>@U

$subject = '..some code here..
<a href=\"members/username1.12345/\" class=\"username bigs\" title=\"\">Username 1</a>
..some code here..
..some code here..
<a href=\"members/username2.55334/\" class=\"username bigs\" title=\"\">Username 2</a>
..some code here..
..some code here..
<a href=\"members/username3.23455/\" class=\"username bigs\" title=\"\">Username 3</a>
..some code here..
..some code here..
<a href=\"members/username4.45545/\" class=\"username bigs\" title=\"\">Username 4</a>
..some code here..';

$pattern = '@<a href="members/.+/" class="username bigs" title="">(.+)</a>@U';

$result = preg_match_all($pattern, $subject, $subpattern);

echo '<pre>'.print_r($subpattern, TRUE).'</pre>';

获取所有<a> tags with class in php</a>的内容

1 个答案: