Question

我有一个二十一点程序，它使用一个满整数的向量来模拟卡片组：

vector<short int> deck;

并用1-10填充它：

for (int i=0; i<=4; ++i) // Populate the deck with 1-10
{
    for (int c=1; c<=10;++c)
    {
        deck.push_back(c);
    }
}
for (i=0; i<=12;++i)
{
    deck.push_back(10); // Face cards
}

然后播种随机数生成器：

srand(time(0)+1);

并尝试使用random_shuffle(deckofcards.begin(), deckofcards.end());对牌组进行随机播放，但是，当用户决定点击时，他们发牌的牌是整个游戏的精确相同，这里有一些示例输出：

Dealer: I'm gonna play it safe
Dealer bets $42
Dealing cards...
Dealer lays down a 5
You have a 3, and a 10 and your total is 13
Stand, or hit? Stand, or hit? hit
You have been dealt an Ace, your hand is soft, and your total is now 14
Stand, or hit? hit
You have been dealt an Ace, your hand is soft, and your total is now 15
Stand, or hit? hit
You have been dealt an Ace, your hand is soft, and your total is now 16
Stand, or hit? hit
You have been dealt an Ace, your hand is soft, and your total is now 17
Stand, or hit? hit
You have been dealt an Ace, your hand is soft, and your total is now 18
Stand, or hit? hit
You have been dealt an Ace, your hand is soft, and your total is now 19
Dealer calls stand
The dealer has a 3, a 10, an Ace , an Ace , an Ace , an Ace , an Ace , an Ace    for      total of 17, you have a 3, a 10, an Ace , an Ace , an Ace , an Ace , an Ace , an         Ace  you win 1042!

如果有帮助，这里是用户键入hit时的代码：

playerhand.push_back(deck.front());
ptotal+=playerhand.back();
if (playerhand.back()!=1)
cout << "You have been dealt a "<<playerhand.back()<<", your total is now"<<ptotal<<endl;
else
    cout << "You have been dealt an Ace, your hand is soft, and your total is now "<<ptotal<<endl;
dealerhand.push_back(deck.front());
dtotal+=dealerhand.back();

但是，此代码可以使用，但可以使用两张卡：

cout << "Dealing cards...\n";
playerhand.clear();
dealerhand.clear();
playerhand.push_back(deck.back());
deck.pop_back();
dealerhand.push_back(deck.back());
deck.pop_back();
if (dealerhand.back()==1)
    dhsoft=true;
else
    dhsoft=false;
if (playerhand.back()==1)
{
    phsoft=true;
    cout << "Your hand is soft\n";
}
else
    phsoft=false;
playerhand.push_back(deck.back());
deck.pop_back();
dealerhand.push_back(deck.back());
deck.pop_back();
if (dealerhand.back()==1)
    dhsoft=true;
else
    dhsoft=false;
if (playerhand.back()==1)
{
    cout << "Your hand is soft\n";
    phsoft=true;
}
else
    phsoft=false;
unsigned int i;
for (i=0;i<=dealerhand.size()-1; ++i)
    dtotal+=dealerhand[i];
for (i=0;i<=playerhand.size()-1; ++i)
    ptotal+=playerhand[i];

那么，为什么上面的代码可以工作，但是当用户输入“命中”不起作用时呢？而且，更重要的是，我该如何解决它（没有代码！）？

Answer 1

它一遍又一遍地返回同一张卡片的原因是deck.front()只返回对前面元素的引用，它不会删除它。但由于vector没有方便的方法来实际删除前面元素，我建议只删除后面的元素：

playerhand.push_back(deck.back());
deck.pop_back();

无论如何，套牌是随机的，无论你处理的是哪种方式都无关紧要。

C ++ random_shuffle（）表现不正常

1 个答案: