Question

我需要使用Post-Redirect-Get显示数据，我在“索引”页面的“信息”页面中输入了数据。我有以下方法，但它不起作用。它甚至没有重定向我提交。我做错了什么？

public class HomeController : Controller
{
    public ActionResult Index()
    {
        return View();
    }

    public ActionResult About()
    {
        return View();
    }

    public ActionResult Information()
    {
        return View();
    }

    //Get info
    [HttpGet]
    public ActionResult Submit(Models.Information FirstName,
                               Models.Information LastName,
                               Models.Information DateOfBirth,
                               Models.Information HourOfBirth,
                               Models.Information NumberOfKids,
                               Models.Information Emso,
                               Models.Information Email,
                               Models.Information PlaceOfBirth)
    {
        if (ModelState.IsValid)
        {
            Models.Information info = new Models.Information();

            info.FirstName = FirstName.ToString();
            info.LastName = LastName.ToString();
            info.DateOfBirth = Convert.ToDateTime(DateOfBirth);
            info.HourOfBirth = Convert.ToDateTime(HourOfBirth);
            info.NumberOfKids = Convert.ToInt32(NumberOfKids);
            info.Emso = Emso.ToString();
            info.Email = Email.ToString();
            info.PlaceOfBirth = PlaceOfBirth.ToString();

            TempData["info"] = info;

            return RedirectToAction("Summary");
        }

        return View();
    }

    //Show info
    [HttpPost]
    public ActionResult Post(Models.Information info)
    {
        info.FirstName = ViewData["FirstName"].ToString();
        info.LastName = ViewData["LastName"].ToString();
        info.DateOfBirth = Convert.ToDateTime(ViewData["DateOfBirth"]);
        info.HourOfBirth = Convert.ToDateTime(ViewData["HourOfBirth"]);
        info.NumberOfKids = Convert.ToInt32(ViewData["NumberOfKids"]);
        info.Emso = ViewData["Emso"].ToString();
        info.Email = ViewData["Email"].ToString();
        info.PlaceOfBirth = ViewData["PlaceOfBirth"].ToString();

        return View();
    }
}

我尝试在Index页面上显示数据：

 First name: <input type='text' runat="server" value="@ViewData["FirstName"]" /><br />

Answer 1

您的代码看起来有点令我困惑，我不确定您要完成的任务。但首先，让我们用一个例子来说明你想要实现的想法。

用户输入有关信息操作/视图的信息
（POST）将其发布到控制器/操作，然后验证模型并将其放入ViewData（REDIRECT TO STEP 3）
（GET）您想在摘要页面上重新显示此数据。

根据这些假设，让我们稍微清理一下你的代码，利用ViewData和TempData对象，看看我们是否可以做到这一点。

信息行动

public ActionResult Information()
    {
        //In a strongly typed view, typically you would send an empty model
        //so the model binder/Html.Input helpers have something to bind to
        return View(new Models.Information());
    }

用于处理传入数据的信息POST

[HttpPost]
public ActionResult Information(Models.Information info)
{
    //Yup - you can use the same action name as the GET action above
    //You can name this anything you want, but I typically keep the same names so 
    //I know where the data came from

    //I think your assignments are backwards.  info came into the controller action
    //You want to save this as ViewData.  Also, let's do that in one line of code
    //And since we are redirecting, lets use the TempData dictionary

    //Notice the method type decorator above [HttpPost].  This is the P in PRG (Post)

if(modelState.IsValid()){
    TempData["info"] = info;

    //Notice the name of the ActionMethod below.  The is the R in PRG (Redirect)
    return RedirectToAction("Summary");
}

//There were errors, lets send back to the Information view
return View(info);

}

摘要行动

public ActionResult Summary()
    {
        //We were redirected here, and this is a GET method.  This is the G in PRG
        //(GET)

        //lets go ahead and set the TempData stuff to a model, it just looks nicer on
        //the view
        var model = TempData["info"];
        return View(model);
    }

至于观点，这里是每个人看起来很棒的片段

信息查看

@model Models.Information

@{using(Html.BeginForm()){
   @Html.LabelFor(x=>x.FirstName)<br/>
   @Html.TextBoxFor(x=>x.Firstname)

   //Repeat for each property

   <input type="Submit" value="Submit"/>
}}

摘要视图

@model Models.Information

   @Html.LabelFor(x=>x.FirstName)<br/>
   @Html.DisplayFor(x=>x.Firstname)

   //Repeat for each property

重定向后 - 在MVC3中获取问题

1 个答案: