我想扩展我的小组(图像和某些东西)。
group.setScale(zoom, zoom);
但是当我扩展我的小组时,我认为这不是我小组的中心。我觉得这就像这样
我希望它像中心一样从中心扩展
我尝试了更多,但并不成功。我怎么能这样做,谢谢。
答案 0 :(得分:2)
[编辑以更好地满足提问者的需求]
以下是如何从中心点缩放Kinetic组
首先,我们存储原始组的centerX和centerY,以便我们可以将组保持在那里:
group.cx=group.getX()+group.getWidth()/2;
group.cy=group.getY()+group.getHeight()/2;
然后我们编写一个自定义缩放方法,它既缩放组又重新集中它:
group.scale=function(x,y){
group.setScale(x,y);
group.setPosition(
group.cx-group.getWidth()/2*group.getScale().x,
group.cy-group.getHeight()/2*group.getScale().y);
group.draw();
}
这是代码和小提琴:http://jsfiddle.net/m1erickson/dVGGz/
<!DOCTYPE HTML>
<html>
<head></head>
<body>
<button id="larger">Larger</button>
<div id="container"></div>
<script src="http://d3lp1msu2r81bx.cloudfront.net/kjs/js/lib/kinetic-v4.4.0.min.js"></script>
<script type="text/javascript" src="http://code.jquery.com/jquery.min.js"></script>
<script>
$(function(){
var stage = new Kinetic.Stage({
container: 'container',
width: 400,
height: 400
});
var layer = new Kinetic.Layer();
// Be sure to set width and height
// They are required for this method to work
var group = new Kinetic.Group({
x: 100,
y: 100,
width:100,
height:100
});
// store the original group center
// so we can center the group there
group.cx=group.getX()+group.getWidth()/2;
group.cy=group.getY()+group.getHeight()/2;
// custom scale function to both
// scale the group and center the results
group.scale=function(x,y){
group.setScale(x,y);
group.setPosition(
group.cx-group.getWidth()/2*group.getScale().x,
group.cy-group.getHeight()/2*group.getScale().y);
group.draw();
}
var box1 = new Kinetic.Rect({
x: 0,
y: 0,
width: 50,
height: 50,
fill: "blue",
stroke: 'black',
strokeWidth: 4
});
group.add(box1);
var box2 = new Kinetic.Rect({
x: 50,
y: 50,
width: 50,
height: 50,
fill: "green",
stroke: 'black',
strokeWidth: 4
});
group.add(box2);
layer.add(group);
stage.add(layer);
var scaleFactor=1;
$("#larger").click(function(){
scaleFactor+=0.10;
group.scale(scaleFactor,scaleFactor);
console.log(scaleFactor);
});
});
</script>
</body>
</html>
答案 1 :(得分:0)
您是否尝试过使用偏移属性?即偏移量:[宽度/ 2,高度/ 2]
答案 2 :(得分:0)
问题#1:我需要从中心扩展一个组。 问题2:除非在创建时明确设置宽度,否则Kinetic JS group.getWidth()和group.getHeight()不起作用。 问题3:我不知道宽度和高度,我正在动态地改变形状。
这意味着为了尝试你的代码,我将不得不编写自己的getWidth和getHeight函数。然后我可以使用你提出的方法。
以下解决方案。
(可能有更好的方法,但这是我现在的编程水平......如果有人可以添加递归来查看包含组等组的组,那就太好了。)
var results = getGroupMinsAndMaxes(myKineticGroup);
console.log('results: '+ results.groupMinX, results.groupMaxX,
results.groupMinY, results.groupMaxY);
function getGroupMinsAndMaxes( group ) {
// note this does not handle children that are groups,
// it expects children to be shapes
var item;
var groupMinX = 99999;
var groupMaxX = -99999;
var groupMinY = 99999;
var groupMaxY = -99999;
var shapeFunctionDefinition = '';
var bounds = {};
for (var i = 0; i < group.children.length; i++ ) {
item = group.children[ i ];
if ( item.getType() !== 'Shape' ) {
alert('The getGroupMinsAndMaxes function is not designed to handle groups that contain groups.');
break;
} else {
shapeFunctionDefinition = item.attrs.drawFunc.toString();
bounds = getShapeMinsAndMaxes( shapeFunctionDefinition );
if ( bounds.shapeMinX < groupMinX ) { groupMinX = bounds.shapeMinX; }
if ( bounds.shapeMaxX > groupMaxX ) { groupMaxX = bounds.shapeMaxX; }
if ( bounds.shapeMinY < groupMinY ) { groupMinY = bounds.shapeMinY; }
if ( bounds.shapeMaxY > groupMaxY ) { groupMaxY = bounds.shapeMaxY; }
}
}
return {
groupMinX: groupMinX,
groupMaxX: groupMaxX,
groupMinY: groupMinY,
groupMaxY: groupMaxY
};
}
function getShapeMinsAndMaxes( shape ) {
// the shape definition is passed as a string
var regex = /[+-]?\d+\.\d+/g;
var floats = shape.match(regex).map(function (v) {
return parseFloat(v);
});
// preset some unrealistically large numbers which
// we will never encounter
var shapeMinX = 99999;
var shapeMaxX = -99999;
var shapeMinY = 99999;
var shapeMaxY = -99999;
for (var i = 0; i < floats.length; i++) {
if (isOdd(i)) {
// Check Y values
if (floats[i] < shapeMinY) {
shapeMinY = floats[i];
}
if (floats[i] > shapeMaxY) {
shapeMaxY = floats[i];
}
} else {
// Check X values
if (floats[i] < shapeMinX) {
shapeMinX = floats[i];
}
if (floats[i] > shapeMaxX) {
shapeMaxX = floats[i];
}
}
}
return {
shapeMinX: shapeMinX,
shapeMaxX: shapeMaxX,
shapeMinY: shapeMinY,
shapeMaxY: shapeMaxY
};
}
function isOdd(num) {
return num % 2;
}
答案 3 :(得分:0)
最简单的方法是重新定位/居中偏移。所有缩放和移动都将基于您的新偏移位置。
group.offset({x:group.width()*。5,y:group.height()* .5});