Question

这是我的查询

     $query="SELECT parent.name, parent.depth
        FROM  address AS node,
                address AS parent
        WHERE node.name LIKE '%".$name."%' AND   
        node.lft BETWEEN parent.lft AND parent.rgt   
        order by node.lft, parent.rgt";

这是我的表结构：

name        |lft | rgt | depth|
------------+----+-----+------+
Australia   | 1  | 10  |  1   |
nsw         | 2  | 9   |  2   |
sydney      | 3  | 8   |  3   |
kensington  | 4  | 5   |  4   |
kingsford   | 6  | 7   |  4   |
------------+----+-----+---- -+

让我们假设$name = k然后结果将是

name        |depth|
------------+-----+
kingsford   | 4   |
sydney      | 3   | 
nsw         | 2   | 
Australia   | 1   |
kensington  | 4   | 
sydney      | 3   | 
nsw         | 2   | 
Australia   | 1   |

我会像这样介绍他们：

-->kensington, sydney, nsw, australia
-->kingsford, sydney, nsw, australia

我无法将此限制为最多只能覆盖10个地址。如果我添加了limit 2，例如它将不会显示上面的两个地址。它只会显示-->kensington, sydney。我怎么能这样做？

Answer 1

也许问题不太清楚，但如果我理解正确，我会使用这样的东西：

SELECT
  GROUP_CONCAT(parent.name ORDER BY parent.depth DESC) AS name
FROM
  address AS node JOIN address AS parent
  ON node.lft BETWEEN parent.lft AND parent.rgt  
WHERE node.name LIKE '%k%'
GROUP BY node.name
LIMIT 10

请参阅小提琴here。

修改

您可能还想使用它，以原始格式返回行：

SELECT parent.name, parent.depth FROM (SELECT name, lft FROM address WHERE name LIKE '%k%' LIMIT 10) AS node, address AS parent WHERE node.lft BETWEEN parent.lft AND parent.rgt order by node.lft, parent.rgt

限制结果的方式不同

1 个答案: