我有这些表格:
我想获得每个主题的最新通知。
SELECT id_theme, n.id
FROM notice_theme
LEFT JOIN (
SELECT id, cdate
FROM notice
ORDER BY cdate DESC
) AS n ON notice_theme.id_notice = n.id
GROUP BY id_theme
结果不好。一个主意 ?感谢。
答案 0 :(得分:6)
有很多方法可以解决这个问题,但我习惯这样做。需要额外的子查询来单独计算每cDate
的最新ID
。
SELECT a.*, c.*
FROM theme a
INNER JOIN notice_theme b
ON a.ID = b.id_theme
INNER JOIN notice c
ON b.id_notice = c.ID
INNER JOIN
(
SELECT a.id_theme, MAX(b.DATE_CREATE) max_date
FROM notice_theme a
INNER JOIN notice b
ON a.ID_Notice = b.ID
GROUP BY a.id_theme
) d ON b.id_theme = d.id_theme AND
c.DATE_CREATE = d.max_date