我收到了这个错误:
HTTP 599:连接关闭[E 130405 11:43:14 web:1031]未捕获 异常GET / networks / 1 / sensors / 1 / alarm(127.0.0.1)
执行以下代码时:
from tornado.stack_context import ExceptionStackContext
def handle_exc(*args):
print('Exception occured')
return True
@tornado.gen.engine
def check_status_changes(netid, sensid):
como_url = "".join(['http://131.114.52:44444/ztc?netid=', str(netid), '&sensid=', str(sensid), '&start=-5s&end=-1s'])
http_client = AsyncHTTPClient()
response = yield tornado.gen.Task(http_client.fetch, como_url)
if response.error is not None:
print("Terzo")
print response.error
with ExceptionStackContext(handle_exc):
response.rethrow()
else:
print('Handle request')
for line in response.body.split("\n"):
if line != "":
#net = int(line.split(" ")[1])
#sens = int(line.split(" ")[2])
#stype = int(line.split(" ")[3])
value = int(line.split(" ")[4])
print value
yield value
return
class AlarmHandler(BaseHandler):
@tornado.web.authenticated
@tornado.web.asynchronous
@tornado.gen.engine
def get(self, netid, sensid):
self.lock_tables("read", ['devices'])
status = self.db.get("SELECT status from devices \
WHERE id=%s AND network_id=%s", sensid, netid)
print("Primo")
print status
try:
periodic = tornado.ioloop.PeriodicCallback(check_status_changes(netid, sensid), 5000)
value = periodic.start()
print("Secondo")
print value
except:
print("Quarto")
periodic.stop()
self.finish()
return
if value != status['status']:
self.lock_tables("write", ['devices'])
self.db.execute("UPDATE devices SET status=%s \
WHERE id=%s AND network_id=%s", value, netid, sensid)
self.unlock_tables()
self.notice("Status changed")
在班级AlarmHandler
中有一个名为check_status_changes
的周期例程。在这个函数中,当有response.error时,我获得了标题的错误。
如何设置错误条件以便返回班级并管理情况?谢谢。
其他信息
如果我做一个龙卷风的屏幕,我会看到:
Primo
{'status':无}
Secondo
无
Terzo
HTTP 599:连接已关闭
发生异常
所以,我认为程序会在异常发生之前关闭连接!
在html consolle中我看到了这个错误:
文件“./wsn.py”,第226行,在check_status_changes中 for response in response.body.split(“\ n”):AttributeError:'NoneType'对象没有属性'split'
答案 0 :(得分:0)
你提出异常:
if response.error:
print("Terzo")
print response.error
raise Exception(response.error)
return
这将是Uncaught Exception
。您应该对此进行编码以处理异常,而不会引发异常。例如。记录错误消息并中止数据库更新。