我有Mysql程序,它将返回5个表,现在我需要将这些表设置为单个Excel文件5个不同的表。 我正在使用VS 2010,Jquery,ASP.Net。 如何在新工作表的excel文件中编写该表。
$("#btnExcel").click(function (e) {
$('#divExcelExporting').html($('#containerOne').html());
$('#divExcelExporting').append($('#containerTwo').html());
$('#divExcelExporting').append($('#containerThree').html());
$('#divExcelExporting').append($('#containerFour').html());
$('#divExcelExporting').append($('#containerFive').html());
var trcoll = $('#divExcelExporting').find('.border-middle1').find('tr');
$.each(trcoll, function (d, f) {
$($(this).find('td')[0]).remove();
});
var trcol2 = $('#divExcelExporting').find('.border-middle2').find('tr');
$.each(trcol2, function (d, f) {
$($(this).find('td')[0]).remove();
});
var trcol3 = $('#divExcelExporting').find('.border-middle3').find('tr');
$.each(trcol3, function (d, f) {
$($(this).find('td')[0]).remove();
});
var trcol4 = $('#divExcelExporting').find('.border-middle4').find('tr');
$.each(trcol4, function (d, f) {
$($(this).find('td')[0]).remove();
});
var trcol5 = $('#divExcelExporting').find('.border-middle5').find('tr');
$.each(trcol5, function (d, f) {
$($(this).find('td')[0]).remove();
});
WebService.SetVendorHTML($('#divExcelExporting').html(), OnWSRequestComplete);
});
答案 0 :(得分:0)
我从OpenXML获得了解决方案。
string path = Context.Server.MapPath("~/ExcelData/test.xslx");
ExportDataSet(ds, path);
private void ExportDataSet(DataSet ds, string destination)
{
using (var workbook = SpreadsheetDocument.Create(destination, DocumentFormat.OpenXml.SpreadsheetDocumentType.Workbook))
{
var workbookPart = workbook.AddWorkbookPart();
workbook.WorkbookPart.Workbook = new DocumentFormat.OpenXml.Spreadsheet.Workbook();
workbook.WorkbookPart.Workbook.Sheets = new DocumentFormat.OpenXml.Spreadsheet.Sheets();
foreach (System.Data.DataTable table in ds.Tables)
{
var sheetPart = workbook.WorkbookPart.AddNewPart<WorksheetPart>();
var sheetData = new DocumentFormat.OpenXml.Spreadsheet.SheetData();
sheetPart.Worksheet = new DocumentFormat.OpenXml.Spreadsheet.Worksheet(sheetData);
DocumentFormat.OpenXml.Spreadsheet.Sheets sheets = workbook.WorkbookPart.Workbook.GetFirstChild<DocumentFormat.OpenXml.Spreadsheet.Sheets>();
string relationshipId = workbook.WorkbookPart.GetIdOfPart(sheetPart);
uint sheetId = 1;
if (sheets.Elements<DocumentFormat.OpenXml.Spreadsheet.Sheet>().Count() > 0)
{
sheetId =
sheets.Elements<DocumentFormat.OpenXml.Spreadsheet.Sheet>().Select(s => s.SheetId.Value).Max() + 1;
}
DocumentFormat.OpenXml.Spreadsheet.Sheet sheet = new DocumentFormat.OpenXml.Spreadsheet.Sheet() { Id = relationshipId, SheetId = sheetId, Name = table.TableName };
sheets.Append(sheet);
DocumentFormat.OpenXml.Spreadsheet.Row headerRow = new DocumentFormat.OpenXml.Spreadsheet.Row();
List<String> columns = new List<string>();
foreach (System.Data.DataColumn column in table.Columns)
{
columns.Add(column.ColumnName);
DocumentFormat.OpenXml.Spreadsheet.Cell cell = new DocumentFormat.OpenXml.Spreadsheet.Cell();
cell.DataType = DocumentFormat.OpenXml.Spreadsheet.CellValues.String;
cell.CellValue = new DocumentFormat.OpenXml.Spreadsheet.CellValue(column.ColumnName);
headerRow.AppendChild(cell);
}
sheetData.AppendChild(headerRow);
foreach (System.Data.DataRow dsrow in table.Rows)
{
DocumentFormat.OpenXml.Spreadsheet.Row newRow = new DocumentFormat.OpenXml.Spreadsheet.Row();
foreach (String col in columns)
{
DocumentFormat.OpenXml.Spreadsheet.Cell cell = new DocumentFormat.OpenXml.Spreadsheet.Cell();
cell.DataType = DocumentFormat.OpenXml.Spreadsheet.CellValues.String;
cell.CellValue = new DocumentFormat.OpenXml.Spreadsheet.CellValue(dsrow[col].ToString()); //
newRow.AppendChild(cell);
}
sheetData.AppendChild(newRow);
}
}
}
}
参考文献:
using DocumentFormat.OpenXml.Packaging;
using DocumentFormat.OpenXml.Spreadsheet;
using DocumentFormat.OpenXml;