Question

sqlwriterow函数我发送一个查询并从我正在寻找的特定行中检索数据。当我发送包含powershell变量的查询时，我遇到了问题。现在，如果我键入26（或任何我正在寻找的ID），我将获得预期的数据，而不是写'$ id'。但是，如果我输入变量，我将得不到任何数据。然后玩弄格式，比如取出我会得到的报价

您的SQL语法有错误;检查手册对应于您的MariaDB服务器版本，以获得正确的语法靠近''第1行

我已经尝试了各种方法来格式化它比如

$sqlcmd4appcheck = "use spree; select * from tasks_profiles where id = '$id'"
$sqlcmd4appcheck = "use spree; select * from tasks_profiles where id = ``$id``"
$sqlcmd4appcheck = "use spree; select * from tasks_profiles where id = ''$id''"
$sqlcmd4appcheck = "use spree; select * from tasks_profiles where id = "$id""

代码：

function sqlwriterow($args1, $args2) {
    [void][system.reflection.Assembly]::LoadFrom(“C:\Program Files (x86)\MySQL\MySQL Connector Net 5.0.9\Binaries\.NET 2.0\MySQL.Data.dll”)
    $dbconnect = New-Object MySql.Data.MySqlClient.MySqlconnection
    $dbconnect.connectionString = "server=207.52.55.122;user id=spree;pwd=spr33Adm1n;database=spree"
    if (-not ($dbconnect.State -like "Open")) { $dbconnect.Open() }
    $sql = New-Object MySql.Data.MySqlclient.MySqlcommand
    $sql.Connection = $dbconnect
    $sql.Commandtext = $args1
    $dataset=New-Object system.Data.Dataset
    $dataAdaptor=New-Object MySql.Data.MySqlClient.MySqlDataAdapter($sql)
    $dataAdaptor.fill($dataset)
    $script:row = $dataset.tables[0].Rows[0].$args2
    $dbconnect.Close()

}


$id = 26
$sqlcmd4appcheck = "use spree; select * from tasks_profiles where id = '$id'"

sqlwriterow -args1 $sqlcmd4appcheck -args2 "app"; $app = $row

带变量的Powershell MYSQL查询语法

0 个答案: