Question

我正在尝试为我的桌子获取行号。到目前为止，这是我的SQL提示符：

SELECT @i = @i + 1 AS Rank, x.Name, x.PartyName, x.ConstituencyName, x.Votes 
FROM (
    SELECT CONCAT(t1.Firstname, ' ', t1.Lastname) AS Name, t1.PartyName, t1.ConstituencyName, COALESCE(t2.Count, 0) AS Votes
        FROM (
            (SELECT db.user.PID, db.user.Firstname, db.user.Lastname, db.party.PartyName, db.constituency.ConstituencyName 
                FROM db.user
                LEFT JOIN db.party ON db.user.PartyId = db.party.PartyID 
                LEFT JOIN db.constituency ON db.user.CID = db.constituency.CID
                WHERE db.user.PartyId IS NOT NULL
                AND db.user.CID IS NOT NULL
            ) t1
            LEFT JOIN
            (SELECT db.user.Vote, COUNT(*) AS 'Count' 
                FROM db.user 
                GROUP BY db.user.Vote
            ) t2
        ON
            t1.PID = t2.Vote
        ORDER BY t2.Count DESC)
        ) x,
(SELECT @i:=1) r

所以这基本上是这样的，首先我创建一个表t1（从2个不同的表中获取信息）然后将它与表t2连接起来，这样我就能得到每个候选人的总票数。然后我将该表标记为'x'并将其与表'r'连接起来，该表应初始化行号（使用行号的在线教程）。但是，当我运行此SQL提示时，我得到以下内容：

Rank    Name    PartyName   ConstituencyName    Votes
0       Name1   Party1      Constituency1       700
0       Name2   Party1      Constituency1       550

任何建议都将不胜感激。

Answer 1

这是用户变量，您应该使用:=而不是=

SELECT @i := @i + 1 AS Rank,...

表的MySQL行号

1 个答案: