JGit:如何获得分支的所有提交? (无需更改工作目录......)

时间:2013-04-04 22:03:03

标签: java jgit

如何在不更改工作目录的情况下获取JGit分支的所有提交?

不幸的是,JGit文档不是很好......

用砂砾红宝石很容易:

repo = Grit::Repo.new(pathToRepo)

repo.commits(branchName, false).each do |commit|
    doSomethingWithTheCommit
end

再见 hurik

6 个答案:

答案 0 :(得分:15)

首先在此尝试:https://stackoverflow.com/a/13925765/2246865

但它始终没有工作,所以我在这里找到了这个:http://www.eclipse.org/forums/index.php/t/280339/

在这里我的解决方案,它并不是很好,但它正在工作......

public static void main(String[] args) throws IOException, GitAPIException {
    Repository repo = new FileRepository("pathToRepo/.git");
    Git git = new Git(repo);
    RevWalk walk = new RevWalk(repo);

    List<Ref> branches = git.branchList().call();

    for (Ref branch : branches) {
        String branchName = branch.getName();

        System.out.println("Commits of branch: " + branch.getName());
        System.out.println("-------------------------------------");

        Iterable<RevCommit> commits = git.log().all().call();

        for (RevCommit commit : commits) {
            boolean foundInThisBranch = false;

            RevCommit targetCommit = walk.parseCommit(repo.resolve(
                    commit.getName()));
            for (Map.Entry<String, Ref> e : repo.getAllRefs().entrySet()) {
                if (e.getKey().startsWith(Constants.R_HEADS)) {
                    if (walk.isMergedInto(targetCommit, walk.parseCommit(
                            e.getValue().getObjectId()))) {
                        String foundInBranch = e.getValue().getName();
                        if (branchName.equals(foundInBranch)) {
                            foundInThisBranch = true;
                            break;
                        }
                    }
                }
            }

            if (foundInThisBranch) {
                System.out.println(commit.getName());
                System.out.println(commit.getAuthorIdent().getName());
                System.out.println(new Date(commit.getCommitTime() * 1000L));
                System.out.println(commit.getFullMessage());
            }
        }
    }
}

答案 1 :(得分:13)

使用下面的代码,您可以获得分支或标记的所有提交

Repository repository = new FileRepository("/path/to/repository/.git");
String treeName = "refs/heads/master"; // tag or branch
for (RevCommit commit : git.log().add(repository.resolve(treeName)).call()) {
    System.out.println(commit.getName());
}

变量treeName将定义标记或分支。此treeName是分支或标记的完整名称,例如 master 分支的refs/heads/master或{em> v1.0的标记的refs/tags/v1.0

或者,您可以使用gitective API。以下代码与上面的代码相同:

Repository repository = new FileRepository("/path/to/repository/.git");

AndCommitFilter filters = new AndCommitFilter();
CommitListFilter revCommits = new CommitListFilter();
filters.add(revCommits);

CommitFinder finder = new CommitFinder(repository);
finder.setFilter(filters);
String treeName = "refs/heads/master"; // tag or branch
finder.findFrom(treeName);

for (RevCommit commit : revCommits) {
    System.out.println(commit.getName());
}

有些try / catch是必要的,我隐藏它们以缩短代码。 祝你好运。

答案 2 :(得分:2)

我只是想找到一种方法来列出每个分支下的所有提交,我找到了这个帖子。我终于做了一些与我在这里找到的工作有所不同的工作。

public static void main(String[] args) throws IOException, GitAPIException {
    Repository repo = new FileRepository("pathToRepo/.git");
    Git git = new Git(repo);

    List<Ref> branches = git.branchList().call();

    for (Ref branch : branches) {
        String branchName = branch.getName();

        System.out.println("Commits of branch: " + branchName);
        System.out.println("-------------------------------------");

        Iterable<RevCommit> commits = git.log().add(repo.resolve(branchName)).call();

        List<RevCommit> commitsList = Lists.newArrayList(commits.iterator());

        for (RevCommit commit : commitsList) {
            System.out.println(commit.getName());
            System.out.println(commit.getAuthorIdent().getName());
            System.out.println(new Date(commit.getCommitTime() * 1000L));
            System.out.println(commit.getFullMessage());
        }
    }

    git.close();
}

感谢您的帮助

答案 3 :(得分:0)

你是对的,文档应该真的更好。

您可以使用JGit Log command或使用像gitective这样的库,这样可以轻松地迭代提交。您可以查看源代码以了解有关JGit的更多信息。

this SO-question中描述了其他(更复杂的)方法。

答案 4 :(得分:0)

可以通过JGit提供的“log”命令完成更简洁的解决方案:

    Repository repository = new FileRepository("pathToRepo/.git");
    logs = new Git(repository).log()
            .add(repository.resolve("remotes/origin/testbranch"))
            .call();
    count = 0;
    for (RevCommit rev : logs) {
        System.out.println("Commit: " + rev /* + ", name: " + rev.getName() + ", id: " + rev.getId().getName() */);
        count++;
    }
    System.out.println("Had " + count + " commits overall on test-branch");

请参阅full snippet

上的jgit-cookbook

答案 5 :(得分:0)

这似乎有效,但我想添加(ObjectId分支)为活动分支提供一个门,但我似乎需要一个范围

Git git = ...
ObjectId master = git.repository.resolve("refs/heads/master")
ObjectId branch = git.repository.resolve("refs/heads/mybranch")

git.log().addRange(master,branch).call()