我使用AlarmManager启动服务,但由于某种原因,我无法弄清楚服务是否无法启动。
我的onResume()中用于启动服务的代码是:
Intent appIntent = new Intent(cxt, NotificationService.class);
AlarmManager alarmManager = (AlarmManager) getSystemService(ALARM_SERVICE);
PendingIntent penIntent = PendingIntent.getService(this, 0,
appIntent, PendingIntent.FLAG_UPDATE_CURRENT);
alarmManager.cancel(penIntent);
penIntent = PendingIntent.getService(this, 0, appIntent, PendingIntent.FLAG_UPDATE_CURRENT);
Calendar cal = Calendar.getInstance();
cal.set(Calendar.HOUR_OF_DAY, 5);
cal.set(Calendar.MINUTE, 00);
cal.set(Calendar.SECOND, 00);
alarmManager.setRepeating(AlarmManager.ELAPSED_REALTIME_WAKEUP, cal.getTimeInMillis(),
10 * 1000, penIntent);
Manifest包含以下内容:
<uses-permission android:name="android.permission.INTERNET" />
<uses-permission android:name="android.permission.RECEIVE_BOOT_COMPLETED" />
<uses-permission android:name="com.android.alarm.permission.SET_ALARM" />
<uses-permission android:name="android.permission.WAKE_LOCK" />
<application
android:debuggable="true"
android:icon="@drawable/icon"
android:label="@string/app_name" >
<service
android:name="de.brillow.mensa.Speiseplan$NotificationService"
android:enabled="true" />
最后服务本身看起来像这样:
public class NotificationService extends Service {
private WakeLock mWakeLock;
@Override
public IBinder onBind(Intent intent) {
return null;
}
private void handleIntent(Intent intent) {
// obtain the wake lock
PowerManager pm = (PowerManager) getSystemService(POWER_SERVICE);
mWakeLock = pm.newWakeLock(PowerManager.PARTIAL_WAKE_LOCK,
"wakelocktag");
mWakeLock.acquire();
Log.i("PowerManager", "acquired");
// do the actual work, in a separate thread
new PollTask().execute();
}
private class PollTask extends AsyncTask<Void, Void, Void> {
@Override
protected Void doInBackground(Void... params) {
// do stuff!
Log.i("Background", "stuff");
return null;
}
@Override
protected void onPostExecute(Void result) {
// handle your data
int id = 001;
Log.i("Noti", "fication");
NotificationManager mNotifyMng = (NotificationManager) getSystemService(NOTIFICATION_SERVICE);
NotificationCompat.Builder mBuilder = new NotificationCompat.Builder(
Speiseplan.this).setSmallIcon(R.drawable.icon)
.setContentTitle("Test").setContentText("Test!");
mNotifyMng.notify(id, mBuilder.build());
Log.i("Notification", "sent");
stopSelf();
Log.i("Service", "stopped");
}
}
@Override
public void onStart(Intent intent, int startId) {
handleIntent(intent);
}
@Override
public int onStartCommand(Intent intent, int flags, int startId) {
handleIntent(intent);
return START_NOT_STICKY;
}
public void onDestroy() {
super.onDestroy();
mWakeLock.release();
}
}
由于某种原因,通知和Log.i消息都没有出现。我希望你能提供帮助。
提前致谢!
答案 0 :(得分:1)
您不应在AsyncTask
内使用Service
。 AsyncTask
只应用于将结果返回到当前活动的任务,即应在Activity
或Fragment
中定义。doInBackground(...)
。这就是它的设计目标。
在您的情况下,您可以将onPostExecute(...)
和onCreate(...)
中的所有内容放入服务的Activity
。如果需要,请使用线程。如果您需要在Intent
中可视化服务结果,请调用Intent intent=new Intent(context,VisualizingActivity.class);
intent.putExtra("A", "Data A");
intent.putExtra("B", "Data B");
context.startActivity(intent);
并将任何详细信息传递给其他内容,例如。
服务中的调用......
String A= intent.getStringExtra("A");
String B= intent.getStringExtra("B");
活动中的处理......
Notification
如果您只想创建AsyncTask
,可以直接从服务中创建Activity
。不需要{{1}}或{{1}}。
希望这有点帮助......干杯!