Question

应该选中复选框，但它不起作用。我很困惑。

<script type="text/javascript">

function check() {
document.getElementById("1").checked = true;
}
</script>

<form>
<input id="1" type="checkbox" name="please check" value="1">please check<br>
</form>

Answer 1

我在Window Onload上调用它在哪里调用只是传递函数名称

<script type="text/javascript">
    window.onload=check;

    function check() {
    document.getElementById("1").checked = true;
    }
    </script>

    <form>
    <input id="1" type="checkbox" name="please check" value="1">please check<br>
    </form>

Answer 2

以另一种方式命令并删除该功能，这将确保脚本运行时存在该复选框。

jsFiddle

<form>
    <input id="1" type="checkbox" name="please check" value="1">please check<br>
</form>
<script type="text/javascript">
    document.getElementById("1").checked = true;
</script>

或者将其放在文档就绪（jQuery）或窗口加载上。

jsFiddle

window.addEventListener('load', check);
function check() {
    document.getElementById("1").checked = true;
}

Answer 3

试试这个：

<script type="text/javascript">

function check() {
document.getElementById("check1").checked = true;
}

window.onload = check;
</script>

<form>
<input id="check1" type="checkbox" name="please check" value="1">please check<br>
</form>

refer this link also

简单的复选框javascript不起作用

3 个答案: