Question

这是很多相似但不一样的问题，所以我找不到这个问题的解决方案。

我有Spring + JPA（Hibernate）网络应用程序。

上下文配置（data-context.xml）：

<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" 
xmlns:context="http://www.springframework.org/schema/context"
xmlns:jdbc="http://www.springframework.org/schema/jdbc" 
xmlns:tx="http://www.springframework.org/schema/tx"
xsi:schemaLocation="http://www.springframework.org/schema/beans
    http://www.springframework.org/schema/beans/spring-beans-3.2.xsd
    http://www.springframework.org/schema/context
    http://www.springframework.org/schema/context/spring-context-3.2.xsd
    http://www.springframework.org/schema/jdbc 
    http://www.springframework.org/schema/jdbc/spring-jdbc-3.2.xsd
    http://www.springframework.org/schema/tx
    http://www.springframework.org/schema/tx/spring-tx-3.2.xsd">

<bean id="dataSource" class="org.springframework.jdbc.datasource.DriverManagerDataSource">
    <property name="driverClassName" value="org.postgresql.Driver"/>
    <property name="url" value="jdbc:postgresql://localhost:5432/db"/>
    <property name="username" value="postgres"/>
    <property name="password" value="1234"/>
</bean>

<bean id="transactionManager" class="org.springframework.orm.jpa.JpaTransactionManager">
    <property name="entityManagerFactory" ref="emf"/>
</bean>

<tx:annotation-driven transaction-manager="transactionManager" />

<bean id="emf" class="org.springframework.orm.jpa.LocalContainerEntityManagerFactoryBean">
    <property name="dataSource" ref="dataSource"/>
    <property name="jpaVendorAdapter">
        <bean class="org.springframework.orm.jpa.vendor.HibernateJpaVendorAdapter"/>
    </property>
    <property name="packagesToScan" value="com.myapp.mvc.logic.domain"/>
    <property name="jpaProperties">
        <props>
            <prop key="hibernate.dialect">org.hibernate.dialect.PostgreSQLDialect</prop>
            <prop key="hibernate.max_fetch_depth">3</prop>
            <prop key="hibernate.jdbc.fetch_size">50</prop>
            <prop key="hibernate.jdbc.batch_size">10</prop>
            <prop key="hibernate.show_sql">true</prop>
        </props>
    </property>
</bean>

<bean id="validator" class="org.springframework.validation.beanvalidation.LocalValidatorFactoryBean"/>

<context:annotation-config/>

<context:component-scan base-package="com.myapp.mvc.logic" />

DispetcherServlet配置（servlet-context.xml）：

<?xml version="1.0" encoding="UTF-8"?>
<beans:beans xmlns="http://www.springframework.org/schema/mvc"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns:beans="http://www.springframework.org/schema/beans"
xmlns:p="http://www.springframework.org/schema/p"
xmlns:context="http://www.springframework.org/schema/context"
xmlns:security="http://www.springframework.org/schema/security"
xsi:schemaLocation="http://www.springframework.org/schema/mvc 
    http://www.springframework.org/schema/mvc/spring-mvc-3.2.xsd
    http://www.springframework.org/schema/beans 
    http://www.springframework.org/schema/beans/spring-beans-3.2.xsd
    http://www.springframework.org/schema/context 
    http://www.springframework.org/schema/context/spring-context-3.2.xsd
    http://www.springframework.org/schema/security 
    http://www.springframework.org/schema/security/spring-security-3.1.xsd
    ">      

<annotation-driven validator="validator"/>

<resources mapping="/resources/**" location="/resources/" />

<default-servlet-handler/>  

<beans:bean class="org.springframework.web.servlet.view.UrlBasedViewResolver" id="tilesViewResolver">
    <beans:property name="viewClass" value="org.springframework.web.servlet.view.tiles3.TilesView"/>
</beans:bean>

<beans:bean class="org.springframework.web.servlet.view.tiles3.TilesConfigurer" id="tilesConfigurer">
    <beans:property name="definitions">
        <beans:list>
            <beans:value>/WEB-INF/layouts/layouts.xml</beans:value>
            <beans:value>/WEB-INF/views/**/views.xml</beans:value>
        </beans:list>
    </beans:property>
</beans:bean>

<interceptors>
    <beans:bean class="org.springframework.web.servlet.i18n.LocaleChangeInterceptor" p:paramName="lang"/>
</interceptors> 

<beans:bean class="org.springframework.context.support.ReloadableResourceBundleMessageSource"
            id="messageSource"
            p:basenames="classpath:META-INF/i18n/application, classpath:META-INF/i18n/validation_messages"
            />
<beans:bean class="org.springframework.web.servlet.i18n.CookieLocaleResolver"
            id="localeResolver"
            p:cookieName="locale"/>

<beans:bean id="validator" class="org.springframework.validation.beanvalidation.LocalValidatorFactoryBean">
    <beans:property name="validationMessageSource" ref="messageSource"/>
</beans:bean>

<context:component-scan base-package="com.myapp.mvc" />

控制器：

@RequestMapping("/users")
@Controller
public class BankAccountCatalogController {

@Inject
private Functions functions;

@RequestMapping(value="/update", method = RequestMethod.POST)
public String catalogBankAccountUpdate(Model uiModel) {
    functions.addUser();
    return "employee_cabinet/catalog_bank_account";
}
}

Functions.class：

@Service("functions")
@Repository
@Transactional
public class Functions {

@PersistenceContext
private EntityManager em;

@Transactional
public void addUser() {
    User user = new User();
    user.setFirstName("John");
    user.setLastName("John");
    user.setMiddleName("John");
    user.setEmail("John@gmail.com");
    user.setPhone(null);
    user.setMd5Password("1234");
    em.persist(user);
    em.flush();
}
}

当我激活控制器时，在em.flush();行中我收到错误：

javax.persistence.TransactionRequiredException: no transaction is in progress

由于某种原因，事务在addUser()函数中不活动。我试过在JUnit环境中运行函数 - 它工作正常。有什么想法吗？

Answer 1

尝试从控制器中删除EntityManager并在控制器上将该方法指定为事务性。

@RequestMapping("/users")
@Controller
public class BankAccountCatalogController {

@Inject
private Functions functions;

@RequestMapping(value="/update", method = RequestMethod.POST)
@Transactional
public String catalogBankAccountUpdate(Model uiModel) {
    functions.addUser();
    return "employee_cabinet/catalog_bank_account";
}
}

还要确保在您是组件扫描的包中指定Functions类，即com.dominform.mvc.logic。

<context:component-scan base-package="com.dominform.mvc.logic" />

Answer 2

解决。这是DispetcherServlet的错误配置。

而不是

<context:component-scan base-package="com.myapp.mvc" />

在servlet-context.xml中，我写了

<context:component-scan base-package="com.myapp.mvc.web.controller" />

它有效。

有用主题：Spring @Transactional - javax.persistence.TransactionRequiredException

Spring webmvc框架中的TransactionRequiredException

2 个答案: