文本字段的Javascript电话面具与正则表达式

时间:2013-04-04 03:39:28

标签: javascript regex input string-formatting mask

我正在使用此功能来触摸屏幕并且几乎完美地工作。

function mask(o, f) 
{ 
    v_obj = o; 
    v_fun = f; 
    setTimeout("execmask()", 1) 
};

function execmask() 
{ 
    v_obj.value = v_fun(v_obj.value) 
};

function mphone(v){
    v=v.replace(/\D/g,"");           
    v=v.substring(0, 11);
    v=v.replace(/^(\d{2})(\d)/g,"(OXX$1) $2"); 
    v=v.replace(/(\d)(\d{4})$/,"$1-$2"); 
    return v;
}

这里我在文本字段中运行掩码:

<input type="text" id="phone" name="phone" onkeypress="mask(this, mphone);" onblur="mask(this, mphone);" />

问题是我需要更改(0XX $ 1)的代码(OXX $ 1)的这一部分。

9位数的现状:(OXX99)99999-9999

8位数的现状:(OXX99)9999-9999

我需要9位数的正确格式:(0XX99)99999-9999

我需要8位数的正确格式:(0XX99)99999-9999

8位或9位数是用户的选择。

如果我将字符'O'更改为'0',则会导致掩码出错。

请帮忙!

2 个答案:

答案 0 :(得分:5)

function mask(o, f) {
    setTimeout(function () {
        var v = f(o.value);
        if (v != o.value) {
            o.value = v;
        }
    }, 1);
}

function mphone(v) {
    var r = v.replace(/\D/g,"");
    r = r.replace(/^0/,"");
    if (r.length > 10) {
        // 11+ digits. Format as 5+4.
        r = r.replace(/^(\d\d)(\d{5})(\d{4}).*/,"(0XX$1) $2-$3");
    }
    else if (r.length > 5) {
        // 6..10 digits. Format as 4+4
        r = r.replace(/^(\d\d)(\d{4})(\d{0,4}).*/,"(0XX$1) $2-$3");
    }
    else if (r.length > 2) {
        // 3..5 digits. Add (0XX..)
        r = r.replace(/^(\d\d)(\d{0,5})/,"(0XX$1) $2");
    }
    else {
        // 0..2 digits. Just add (0XX
        r = r.replace(/^(\d*)/, "(0XX$1");
    }
    return r;
}

http://jsfiddle.net/BBeWN/

答案 1 :(得分:-3)

我喜欢这个功能,我一直都在使用它。如果有人需要,我已经添加了2个其他面具。我知道他们没有直接回答这个问题,但它们非常有用。

//Social Security Number for USA
 function mssn(v) {
    var r = v.replace(/\D/g,"");
    r = r.replace(/^0/,"");
    if (r.length > 9) {
        r = r.replace(/^(\d\d\d)(\d{2})(\d{0,4}).*/,"$1-$2-$3");
        return r;
    }
    else if (r.length > 4) {
        r = r.replace(/^(\d\d\d)(\d{2})(\d{0,4}).*/,"$1-$2-$3");
    }
    else if (r.length > 2) {
        r = r.replace(/^(\d\d\d)(\d{0,3})/,"$1-$2");
    }
    else {
        r = r.replace(/^(\d*)/, "$1");
    }
    return r;
}

//USA date
function mdate(v) {
   var r = v.replace(/\D/g,"");
   if (r.length > 4) {
    r = r.replace(/^(\d\d)(\d{2})(\d{0,4}).*/,"$1/$2/$3");
   }
   else if (r.length > 2) {
    r = r.replace(/^(\d\d)(\d{0,2})/,"$1/$2");
   }
   else if (r.length > 0){
         if (r > 12) {
           r = "";
         }
   }
   return r;
}