我希望typeahead建议菜单根据所选菜单显示不同的结果,如下所示:
var colors = ["red", "blue", "green", "yellow", "brown", "black"];
var numbers = ["One", "Two", "Three", "Four", "Five", "Six"];
var names = ["Ahmad", "Ali", "Hatem", "Wesam", "Nour", "Jeorge"];
$( "#search1" ).attr("autocomplete", "off");
$( "#search-fld" ).typeahead({source: colors});
$("#search-drop li a").click(function(){
$("#search-btn").text($(this).text());
if($(this).text() == 'People') {
$( "#search-fld" ).typeahead({source: names});
} else if($(this).text() == 'Salaries') {
$( "#search-fld" ).typeahead({source: numbers});
} else if($(this).text() == 'Jobs') {
$( "#search-fld" ).typeahead({source: colors});
}
});
以下是jsfiddle的示例。 但问题是,即使我选择不同的子菜单,也会出现相同的结果。
我想知道如何从不同的资源加载不同的预先输出结果。
请咨询,
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答案 0 :(得分:2)
这应该有效:
$("#search-drop li a").click(function(){
$("#search-btn").text($(this).text());
if($(this).text() == 'People') {
$( "#search-fld" ).data('typeahead').source = names;
} else if($(this).text() == 'Salaries') {
$( "#search-fld" ).data('typeahead').source = numbers;
} else if($(this).text() == 'Jobs') {
$( "#search-fld" ).data('typeahead').source = colors;
}
});