Question

我在我的应用中使用有三列的GridView。你可以在下面看到它。

<GridView
                android:id="@+id/mainMenu"
                android:layout_width="match_parent"
                android:layout_height="fill_parent"
                android:columnWidth="60dp"
                android:gravity="center"
                android:numColumns="3"
                android:stretchMode="columnWidth"
                android:horizontalSpacing="1dp"
                android:verticalSpacing="1dp" >

动态地我想在GridView中的六个不同位置放置6个图像。我已经在这方面开发了一些代码，每次运行代码时，它都会将图像放在错误的位置。实际上我想将image_1放在position_0，image_2放在position_1，image_3放在position_2，依此类推。我怎样才能完成所需的任务。请在这方面帮助我，我将非常感谢你的善举。提前谢谢。

protected void onCreate(Bundle savedInstanceState) 
    {

        super.onCreate(savedInstanceState);

    requestWindowFeature(Window.FEATURE_NO_TITLE);
    setRequestedOrientation(ActivityInfo.SCREEN_ORIENTATION_PORTRAIT); 
    getWindow().addFlags(WindowManager.LayoutParams.FLAG_KEEP_SCREEN_ON); 

    setContentView(R.layout.main);

    grdMainMenu = (GridView) findViewById(R.id.mainMenu);
    grdMainMenu.setAdapter(new ImageAdapter(this));
}



public class ImageAdapter extends BaseAdapter
    {
        Context mContext;
        public ImageAdapter(Context c)
        {
            mContext = c;
        }

        @Override
        public int getCount() 
        {
            // TODO Auto-generated method stub
            return 6;
        }

        @Override
        public Object getItem(int position) 
        {
            // TODO Auto-generated method stub
            return null;
        }

        @Override
        public long getItemId(int position) 
        {
            // TODO Auto-generated method stub
            return 0;
        }

        @Override
        public View getView(int position, View convertView, ViewGroup parent) 
        {
            View v;
            ImageView iv;

            if(convertView ==null)
            {
                LayoutInflater li = getLayoutInflater();
                v = li.inflate(R.layout.icon, null);

                iv = (ImageView)v.findViewById(R.id.icon_image);

                if(position == 0)
                {
                    iv.setImageResource(R.drawable.image1);
                }

                if(position == 1)
                {
                    iv.setImageResource(R.drawable.image2);
                }

                if(position == 2)
                {
                    iv.setImageResource(R.drawable.image3);             

                }

                if(position == 3)
                {
                    iv.setImageResource(R.drawable.image4);             

                }

                if(position == 4)
                {
                    iv.setImageResource(R.drawable.image5);             

                }

                if(position == 5)
                {
                    iv.setImageResource(R.drawable.image6);             

                }

            }

            else
            {
                v = convertView;
            }

            return v;
        }

Answer 1

您可以使用ImageAdapter类和图像的Integer数组。 Imageadapter会将每个图像放在gridview中的所需位置。请参阅Shuffling Gridview items without repeats tried many approaches的答案。检查SimonSays的答案

如何在Android中的不同位置将图像放置在GridView中？

1 个答案: