我试图检查c#中是否有某种类型的类。它会在表单上打印出某些标签,具体取决于它的类型。这是我到目前为止所做的,它适用于" if"声明。但是,我得到一个"错误,无法转换类型"的对象。在这种情况下是否可以使用if-else语句?
public void ShowStaffData(string pName)
{
//Gets Staff Details from the name slected int he list box in the form
people.CreatePeople();
var currentPerson =
people.person.Where(p => p.Forename + " " + p.Surname == pName);
// How the info is printed out if person selected in
// a member of Accademic Staff
AccademicStaff accademic = currentPerson as AccademicStaff;
if (currentPerson!=null)
{
foreach (AccademicStaff accStaff in currentPerson)
{
label9.Text = accStaff.Forename + " " + accStaff.Surname;
label10.Text = accStaff.IdentificationNumber.ToString();
label11.Text = accStaff.DateOfBirth;
label12.Text = accStaff.Address;
label13.Text = accStaff.Office;
label14.Text = accStaff.School;
label15.Text = accStaff.ModuleLeaderOf;
label16.Text = accStaff.ProgramLeaderOf;
}
}
else
{
// How the info is printed out if person selected in
// a member of Admin Staff
foreach (AdminStaff admin in currentPerson)
{
label9.Text = admin.Forename + " " + admin.Surname;
label10.Text = admin.IdentificationNumber.ToString();
label11.Text = admin.DateOfBirth;
label12.Text = admin.Address;
label13.Text = admin.Office;
label6.Text = "Job Role";
label14.Text = admin.JobRole;
label7.Dispose();
label8.Dispose();
label15.Dispose();
label16.Dispose();
}
}
}
答案 0 :(得分:7)
首先,currentPersion
是项目的集合。使用Single
方法将其设为一个项目:
var currentPerson =
people.person.Where(p => p.Forename + " " + p.Surname == pName).Single();
(如果您可能根本没有匹配,则使用SingleOrDefault
,然后检查currentPersion
是否为空。)
其次,在尝试投射后,您正在检查currentPerson
变量而不是accademic
变量:
AccademicStaff accademic = currentPerson as AccademicStaff;
if (accademic != null)
现在你也不需要循环。使用第一部分中的accademic
变量,并在第二部分中将引用转换为AdminStaff
:
AdminStaff admin = currentPerson as AdminStaff;
答案 1 :(得分:2)
将if ... else ...
位移到foreach
循环中,因为where选择器返回的是一个集合,而不是一个人。
var currentPerson = people.person.Where(p => p.Forename + " " + p.Surname == pName);
foreach (var person in currentPerson)
{
AccademicStaff accStaff = person as AccademicStaff;
if (accStaff != null)
{
label9.Text = accStaff.Forename + " " + accStaff.Surname;
label10.Text = accStaff.IdentificationNumber.ToString();
label11.Text = accStaff.DateOfBirth;
label12.Text = accStaff.Address;
label13.Text = accStaff.Office;
label14.Text = accStaff.School;
label15.Text = accStaff.ModuleLeaderOf;
label16.Text = accStaff.ProgramLeaderOf;
}
else
{
// How the info is printed out if person selected in a member of Admin Staff
label9.Text = person.Forename + " " + person.Surname;
label10.Text = person.IdentificationNumber.ToString();
label11.Text = person.DateOfBirth;
label12.Text = person.Address;
label13.Text = person.Office;
label6.Text = "Job Role";
label14.Text = person.JobRole;
}
}
我删除了标签上Dispose()
的来电,没有任何意义。
编辑你可能会有点像这样缩短它:
var currentPerson = people.person.Where(p => p.Forename + " " + p.Surname == pName);
foreach (var person in currentPerson)
{
label9.Text = person.Forename + " " + person.Surname;
label10.Text = person.IdentificationNumber.ToString();
label11.Text = person.DateOfBirth;
label12.Text = person.Address;
label13.Text = person.Office;
AccademicStaff accStaff = person as AccademicStaff;
if (accStaff != null)
{
label14.Text = accStaff.School;
label15.Text = accStaff.ModuleLeaderOf;
label16.Text = accStaff.ProgramLeaderOf;
}
else
{
label6.Text = "Job Role";
label14.Text = person.JobRole;
}
}
答案 2 :(得分:0)
if (instance.GetType().IsClass)
{
}
应该做的伎俩。
但你不应该这样做,如果你需要不同的类来打印不同的东西,那么我建议你去创建一个界面并在每种类型上单独实现它。
答案 3 :(得分:0)
看起来currentPerson
是单个实体而不是集合。所以Single
或FirstOrDefault
也会起作用; (取决于currentPerson是否唯一)然后使用is
测试我喜欢的类型,因为它处理空检查。因此,如果没有填充任何标签,则意味着从linq语句返回的人都不是类型。
people.CreatePeople();
var currentPerson = people.person.Where(p => p.Forename + " " + p.Surname == pName).Single();
if(currentPerson is AcademicStaff)
{
label9.Text = accStaff.Forename + " " + accStaff.Surname;
label10.Text = accStaff.IdentificationNumber.ToString();
label11.Text = accStaff.DateOfBirth;
label12.Text = accStaff.Address;
label13.Text = accStaff.Office;
label14.Text = accStaff.School;
label15.Text = accStaff.ModuleLeaderOf;
label16.Text = accStaff.ProgramLeaderOf;
}
else if(currentPerson is AdminStaff)
{
label9.Text = admin.Forename + " " + admin.Surname;
label10.Text = admin.IdentificationNumber.ToString();
label11.Text = admin.DateOfBirth;
label12.Text = admin.Address;
label13.Text = admin.Office;
label6.Text = "Job Role";
label14.Text = admin.JobRole;
label7.Dispose();
label8.Dispose();
label15.Dispose();
label16.Dispose();
}