SQL Count all Rows

Question

我需要计算查询的计数，但是我遇到了一些问题。

原始查询效果很好 它给了我一行正确的计数（3200）：

select count(e.entity_id) 
from `catalog_product_entity` AS `e`
INNER JOIN `review` AS `rt` 
ON rt.entity_pk_value = e.entity_id
INNER JOIN `review_detail` AS `rdt` 
ON rdt.review_id = rt.review_id
INNER JOIN `review_store` AS `store` 
ON rt.review_id=store.review_id AND store.store_id=0

我需要更改此查询以便现在获取其他值，这是新的计数查询：

select count(e.entity_id) 
from `catalog_product_entity` AS `e`
INNER JOIN `review` AS `rt` 
ON rt.entity_pk_value = e.entity_id
INNER JOIN `review_detail` AS `rdt` 
ON rdt.review_id = rt.review_id
LEFT JOIN `rating_option_vote` AS `vt` 
ON vt.review_id = rt.review_id
INNER JOIN `review_store` AS `store` 
ON rt.review_id=store.review_id AND store.store_id=0 
GROUP BY `rt`.`review_id`

第二个查询不是给我回一行，但是没有正确的计数（3200），而是3200行，每一行都有不同的计数。

我需要的是：

SELECT COUNT (*) FROM
( `second_query`)

或任何其他让我回到正确计数的解决方案

Answer 1

删除group by子句。

Answer 2

试试这个

select TOP 1 count(e.entity_id) OVER() [Total Count]
from `catalog_product_entity` AS `e`
INNER JOIN `review` AS `rt` 
ON rt.entity_pk_value = e.entity_id
INNER JOIN `review_detail` AS `rdt` 
ON rdt.review_id = rt.review_id
LEFT JOIN `rating_option_vote` AS `vt` 
ON vt.review_id = rt.review_id
INNER JOIN `review_store` AS `store` 
ON rt.review_id=store.review_id AND store.store_id=0 
GROUP BY `rt`.`review_id`

或

SELECT COUNT(*)
FROM 
(select `rt`.`review_id`
from `catalog_product_entity` AS `e`
INNER JOIN `review` AS `rt` 
ON rt.entity_pk_value = e.entity_id
INNER JOIN `review_detail` AS `rdt` 
ON rdt.review_id = rt.review_id
LEFT JOIN `rating_option_vote` AS `vt` 
ON vt.review_id = rt.review_id
INNER JOIN `review_store` AS `store` 
ON rt.review_id=store.review_id AND store.store_id=0 
GROUP BY `rt`.`review_id`) AS T1

Answer 3

如果您的查询没有group by，它将隐式地创建整个结果的一组，并获得该单个组的计数。

通过添加group by，您为每次审核创建了一个组，结果就是每个组的计数。

只需从查询中删除group by子句，即可获得整个结果的计数。

Answer 4

试试这个

select TOP 1 count(e.entity_id) OVER (partition by '1')
from `catalog_product_entity` AS `e`
INNER JOIN `review` AS `rt` 
ON rt.entity_pk_value = e.entity_id
INNER JOIN `review_detail` AS `rdt` 
ON rdt.review_id = rt.review_id
LEFT JOIN `rating_option_vote` AS `vt` 
ON vt.review_id = rt.review_id
INNER JOIN `review_store` AS `store` 
ON rt.review_id=store.review_id AND store.store_id=0 
GROUP BY `rt`.`review_id`