我的模型功能是
public function getUser()
{
$this->db->select(array('customer_name','customer_address','phone_no','fax','email_id','contact_person_name','mobile_no'));
$this->db->from('add_customer');
$this->db->where(array('status'=>1));
$res = $this->db->get();
if($res->num_rows() > 0)
{
$rows = $res->result_array();
return $rows;
}else{
return false;
}
}
控制器中的功能
public function search_customer()
{
//$this->load->helper('url');
$data['baseurl'] = base_url();
$this->load->view('templates/header');
$data['details'] = $this->Customer_model->getUser();
$this->load->view('master/customer',$data);
}
从我的视图中提取数据就像这样
<?php for($i=0;$i<count($details);$i++){ ?>
<tr>
<td><?php echo ($i+1); ?></td>
<td><?php echo $details[$i]['customer_name']; ?></td>
<td><?php echo $details[$i]['customer_address']; ?></td>
<td><?php echo $details[$i]['phone_no']; ?></td>
<td><?php echo $details[$i]['email_id']; ?></td>
<td><?php echo $details[$i]['contact_person_name']; ?></td>
<?php }?>
这会导致像这样的错误
A PHP Error was encountered
Severity: Notice
Message: Undefined variable: details
Filename: master/Customer.php
Line Number: 69
任何人请告诉我为什么会出现这个错误
答案 0 :(得分:1)
尝试在控制器中加载模型,如
$this->load->model('Customer_model');
在不加载模型的情况下,您无法从get_user函数
获取详细信息答案 1 :(得分:0)
型号:
public function getUser()
{
$this->db->select('customer_name','customer_address','phone_no',
'fax','email_id','contact_person_name','mobile_no');
$this->db->from('add_customer');
$this->db->where('status',1);
return $this->db->get()->result();
}
控制器:
public function search_customer()
{
$data['baseurl'] = base_url();
//Load the view in variable as data, but do not render
//($header is accessible in 'master/customer' view)
$data['header'] = $this->load->view('templates/header','',true);
//Be sure to load Customer_model
$data['details'] = $this->Customer_model->getUser();
$this->load->view('master/customer',$data);
}
查看:
<?php if(count($details)): ?>
<?php foreach($details as $detail): ?>
<tr>
<td><?php echo $detail->customer_name; ?></td>
<td><?php echo $detail->customer_address; ?></td>
<td><?php echo $detail->phone_no; ?></td>
<td><?php echo $detail->email_id; ?></td>
<td><?php echo $detail->contact_person_name; ?></td>
</tr>
<?php endforeach; ?>
<?php endif; ?>
答案 2 :(得分:-1)
尝试在主/客户中使用$data
代替$details
。