我正在使用[DLLImport]
属性访问.NET代码中的一堆C ++函数。
现在,我通过以下方式完成所有功能:
const string DLL_Path = "path\\to\\my\\dll.dll";
[DllImport(DLL_Path,
CallingConvention = CallingConvention.StdCall,
CharSet = CharSet.Ansi)]
public static extern int MyFunction1();
[DllImport(DLL_Path,
CallingConvention = CallingConvention.StdCall,
CharSet = CharSet.Ansi)]
public static extern ErrorCode MyFunction2(int id);
[DllImport(DLL_Path,
CallingConvention = CallingConvention.StdCall,
CharSet = CharSet.Ansi)]
public static extern ErrorCode MyFunction3(string server, byte timeout,
ref int connection_id, ref DeviceInfo pInfos);
[DllImport(DLL_Path,
CallingConvention = CallingConvention.StdCall,
CharSet = CharSet.Ansi)]
public static extern ErrorCode MyFunction4([MarshalAs(UnmanagedType.LPArray)] byte[] pVersion,
ref int psize);
[DllImport(DLL_Path,
CallingConvention = CallingConvention.StdCall,
CharSet = CharSet.Ansi)]
public static extern ErrorCode MyFunction5(int errorcode,
[MarshalAs(UnmanagedType.LPTStr)] string pmsg, ref int psize);
这并不令人满意:属性的重复似乎效率低下并且破坏了函数原型的可读性。特别是因为我有20或30个函数要导入。
我想知道我是否只能在某个地方拥有[DllImport(DLL_Path, CallingConvention = CallingConvention.StdCall, CharSet = CharSet.Ansi)]
部分并更清楚地识别出函数定义,就像这个伪代码一样:
const string DLL_Path = "path\\to\\my\\dll.dll";
// some code defining a section which tells that the next functions are DLLImport
[DllImport(DLL_Path, CallingConvention = CallingConvention.StdCall, CharSet = CharSet.Ansi)]
{
public static extern int MyFunction1();
public static extern ErrorCode MyFunction2(int id);
public static extern ErrorCode MyFunction3(string server, byte timeout, ref int connection_id, ref DeviceInfo pInfos);
public static extern ErrorCode MyFunction4([MarshalAs(UnmanagedType.LPArray)] byte[] pVersion, ref int psize);
public static extern ErrorCode MyFunction5(int errorcode, [MarshalAs(UnmanagedType.LPTStr)] string pmsg, ref int psize);
}
这可能吗?
我在SO中发现了这个问题:Shorten amount of DllImport in C#?但它建议通过LoadLibrary
和GetProcAddress
动态加载函数,我发现这些函数的可读性较低。
答案 0 :(得分:6)
不,没有办法将属性简化为单个声明。您需要将属性应用于所有方法。
但您至少可以将属性声明缩短为[DllImport(DLL_Path)]
,因为您为CallingConvention
和CharSet
指定的值与默认值相同。