Question

我知道有类似问题，但请耐心等待。我正在帮助我的小表弟在python中创建一个程序，其中一个硬币被翻转1000次并且“玩家”可以说是猜测了多少时间头部出现。然后，她想检查猜测是否在头部出现的次数的10倍之内并且相应地做出反应（骗子你（回答 - 猜测）关闭）或（只做好工作（回答 - 猜测）关闭）。我习惯使用UNIX和python似乎以一种非常不同的方式进行项目。这是代码可能以某种方式使用范围来检查猜测是否在范围内？

#Guess how many times heads will occur when a coin is flipped 1000 time
import random
import time

print('I will flip a coin 1000 times. Guess how many times it will come up heads.     (Press enter to begin)')
int(guess) = input()
flips = 0
heads = 0
while flips < 1000:
    if random.randint(0, 1) == 1:
        heads = heads + 1
    flips = flips + 1

    if flips == 900:
        print('900 flips and there have been ' + str(heads) + ' heads.')
        time.sleep(5)
    if flips == 100:
        print('At 100 tosses, heads has come up ' + str(heads) + ' times so far.')
        time.sleep(2)
    if flips == 500:
        print('Half way done, and heads has come up ' + str(heads) + ' times.')
        time.sleep(2)

print()
print('Out of 1000 coin tosses, heads came up ' + str(heads) + ' times!')
time.sleep(2)
print('Were you close?')
int(answer) = input()

Answer 1

if heads - 10 <= int(guess) <= heads + 10:

替代地

if abs(heads - int(guess)) <= 10:

如何使用python检查值是否在另一个值的10之内

1 个答案: