我正在尝试编写一些JavaScript,允许我在网页上移动div。也就是说,我想这样做,以便您可以单击并将div从页面上的一个位置拖动到另一个位置。我的JavaScript似乎没有合作。但是,我觉得我犯了一个非常简单的错误。也许另一双眼睛可以找到我的问题?
感谢任何评论。
下面是我的JS,CSS和HTML:
JavaScript的:
function getStyle(object, styleName) {
if (window.getComputedStyle) {
return document.defaultView.getComputedStyle(object, null).getPropertyValue(styleName);
} else if (object.currentStyle) {
return object.currentStyle[styleName];
}
}
function grabCalculator(e) {
var evt = e || window.event;
calculator = evt.target || evt.srcElement;
var mousex = evt.clientX;
var mousey = evt.clientY;
diffx = parseInt(calculator.style.left) + mousex;
diffy = parseInt(calculator.style.top) + mousey;
addEvent(document, "mousemove", moveCalculator, false);
addEvent(document, "mouseup", dropCalculator, false);
}
function moveCalculator(e) {
var evt = e || window.event;
var mousex = evt.clientX;
var mousey = evt.clientY;
calculator.style.left = mousex + diffx + "px";
calculator.style.top = mousey + diffy + "px";
}
function addEvent(obj, eventType, fnName, cap) {
alert("TEST");
if (obj.attachEvent) {
obj.attachEvent("on" + eventType, fnName);
} else {
obj.addEventListener(eventType, fnName, cap);
}
}
function removeEvent(obj, eventType, fnName, cap) {
if (obj.attachEvent) {
obj.detachEvent("off" + eventType, fnName);
} else {
obj.removeEventListener(eventType, fnName, cap);
}
}
function dropCalculator(e) {
removeEvent(document, "mousemove", moveCalculator, false);
removeEvent(document, "mouseup", dropCalculator, false);
}
function init() {
diffx = null;
diffy = null;
calculator = document.getElementById("calculator");
//store top and left values of calculator
calculator.style.top = getStyle(calculator, "top");
calculator.style.left = getStyle(calculator, "left");
calcButtonState = true;
}
window.onload = init;
CSS:
#calculator
{
position: absolute;
z-index: 1;
left: 37%;
top: 25%;
border: solid;
border-color: red;
background: black;
width: 25%;
height: 45%;
}
这只是相关的CSS。
HTML:
<!DOCTYPE HTML>
<html>
<head>
<link type="text/css" rel="stylesheet" href="style.css">
<script type="text/javascript" src="javascript.js"></script>
</head>
<body>
<div id="main">
<!--Calculator-->
<div id="calculator">
</div>
<!--End calculator-->
<header>
<div id="title">
Conversion Formulas
</div>
</header>
<nav>
</nav>
<div id="content">
<div id="dryMeasureContent">
</div>
<div id="wetMeasureContent">
</div>
<div id="distanceContent">
</div>
<div id="temperatureContent">
</div>
</div>
<footer>
</footer>
</div>
</body>
</html>
请注意,我的其他HTML标记已经到位,但是,stackoverflow似乎不能很好地处理HTML,因此它们不会出现。
答案 0 :(得分:1)
首先,您的init()
函数不会添加任何事件侦听器 - 这就是问题
尝试在此行之后添加addEvent(calculator, 'mousedown', moveCalculator);
calculator = document.getElementById("calculator");
我希望你理解我的想法
答案 1 :(得分:0)
您是否查看过jquery库可拖动http://jqueryui.com/draggable/和droppable http://jqueryui.com/droppable/?
我已经非常成功地使用了这些库。
超级超级易于实施。
答案 2 :(得分:-1)
W3Schools有一个很棒的拖放教程,只使用HTML5和javascript。
<!DOCTYPE HTML>
<html>
<head>
<script>
function allowDrop(ev){
ev.preventDefault();
}
function drag(ev){
ev.dataTransfer.setData("Text",ev.target.id);
}
function drop(ev){
ev.preventDefault();
var data=ev.dataTransfer.getData("Text");
ev.target.appendChild(document.getElementById(data));
}
</script>
</head>
<body>
<div id="div1" ondrop="drop(event)" ondragover="allowDrop(event)"></div>
<img id="drag1" src="img_logo.gif" draggable="true" ondragstart="drag(event)" width="336" height="69">
</body>
</html>