Question

我有以下示例数据：

Id    Name     Category
-----------------------
1     Joe       A
2     Joe       B
3     Joe       D
4     Mary      A
5     Mary      C
6     Mary      D

我想显示一个人所属的类别：

Name   CategoryA  CategoryB  CategoryC  CategoryD
--------------------------------------------------
Joe       X          X                     X
Mary      X                     X          X

可以使用1和0来代替X和空白。

这对我来说就像一个PIVOT问题。

Answer 1

您可以通过多种方式转换数据。有些使用聚合函数而有些则没有。但即使您正在旋转字符串，您仍然可以应用聚合。

与CASE聚合：

select name,
  max(case when category = 'A' then 'X' else '' end) CategoryA,
  max(case when category = 'B' then 'X' else '' end) CategoryB,
  max(case when category = 'C' then 'X' else '' end) CategoryC,
  max(case when category = 'D' then 'X' else '' end) CategoryD
from yourtable 
group by name

请参阅SQL Fiddle with Demo

静态数据透视：

即使值是字符串，您仍然可以使用PIVOT函数转换数据。如果您有已知数量的类别，则可以对查询进行硬编码：

select name, 
  coalesce(A, '') CategoryA, 
  coalesce(B, '') CategoryB, 
  coalesce(C, '') CategoryC, 
  coalesce(C, '') CategoryD
from
(
  select name, category, 'X' flag
  from yourtable
) d
pivot
(
  max(flag)
  for category in (A, B, C, D)
) piv

请参阅SQL Fiddle with Demo。

动态数据透视：

如果您的类别数量未知，则可以使用动态SQL：

DECLARE @cols AS NVARCHAR(MAX),
    @colsNull AS NVARCHAR(MAX),
    @query  AS NVARCHAR(MAX)

select @cols = STUFF((SELECT  ',' + QUOTENAME(category) 
                    from yourtable
                    group by category
                    order by category
            FOR XML PATH(''), TYPE
            ).value('.', 'NVARCHAR(MAX)') 
        ,1,1,'')

select @colsNull = STUFF((SELECT  ', coalesce(' + QUOTENAME(category)+', '''') as '+QUOTENAME('Category'+category)
                    from yourtable
                    group by category
                    order by category
            FOR XML PATH(''), TYPE
            ).value('.', 'NVARCHAR(MAX)') 
        ,1,1,'')


set @query = 'SELECT name, ' + @colsNull + ' 
              from 
             (
                select name, category, ''X'' flag
                from yourtable
            ) x
            pivot 
            (
                max(flag)
                for category in (' + @cols + ')
            ) p '

execute(@query)

见SQL Fiddle with Demo。

多个联接：

select c1.name,
  case when c1.category is not null then 'X' else '' end as CategoryA,
  case when c2.category is not null then 'X' else '' end as CategoryB,
  case when c3.category is not null then 'X' else '' end as CategoryC,
  case when c4.category is not null then 'X' else '' end as CategoryD
from yourtable c1
left join yourtable c2
  on c1.name = c2.name
  and c2.category = 'B'
left join yourtable c3
  on c1.name = c3.name
  and c3.category = 'C'
left join yourtable c4
  on c1.name = c4.name
  and c4.category = 'D'
where c1.category = 'A'

请参阅SQL Fiddle with Demo

所有查询都会给出结果：

| NAME | CATEGORYA | CATEGORYB | CATEGORYC | CATEGORYD |
--------------------------------------------------------
|  Joe |         X |         X |           |         X |
| Mary |         X |           |         X |         X |

SQL Server 2012 PIVOT没有聚合

1 个答案: