Question

我在Java中定义了两个类。我们称他们为“用户”和“地址”

class Address {
    String addressFirstLine;
    String city;
    String pincode;

    // Getters/setters for all attributes
}

class User {
    String firstName;
    String lastName;
    Address address;

    // Getters/setters for all attributes
}

我创建了User类的对象，并使用Gson库对其进行了序列化。

JSON字符串类似于：

{"firstname":"Zen","lastName":"coder", "Address":{"addressFirstLine":"High st, Point place","city":"Wisconcin","pincode":"4E23C"}}

现在这个字符串被发送到一个python应用程序，该应用程序具有相同的两个类定义'User'和'Address'，其定义与上面的Java完全相同。

我尝试使用jsonpickle将json反序列化为python对象。我可以使用jsonpickle而不是复杂的对象来反序列化简单对象。

有人可以建议解决这个问题吗？

Answer 1

这可能是使用Python内置JSON库的解决方案，利用Python将字典作为关键字参数进行摄取的能力。

我根据你的大纲在Python中定义了类。在User类定义中，我允许将地址作为实际地址对象，列表（从JSON数组转换）或字典（从JSON对象转换）传递。

class Address(object):
def __init__(self, addressFirstLine, city, pincode):
    self.addressFirstLine = addressFirstLine
    self.city = city
    self.pincode = pincode


class User(object):
    def __init__(self, firstName, lastName, address):
        self.firstName = firstName
        self.lastName = lastName
        if isinstance(address, Address):
            self.address = address
        elif isinstance(address, list):
            self.address = Address(*address)
        elif isinstance(address, dict):
            self.address = Address(**address)
        else:
            raise TypeError('address must be provided as an Address object,'
            ' list, or dictionary')

我使用内置的Python json库将您提供的JSON字符串转换为字典，然后使用该字典创建用户对象。如下所示，user.address是一个实际的Address对象（我在一个名为user_address.py的文件中定义了User和Address，因此是前缀）。

>>> import json
>>> user_dict = json.loads('{
    "firstName" : "Zen", "lastName" : "Coder", 
    "address" : {
        "addressFirstLine" : "High st, Point place",
        "city" : "Wisconcin", 
        "pincode" : "4E23C"}
    }')
>>> from user_address import User
>>> user = User(**user_dict)
>>> user
    <user_address.User at 0x1035b4190>
>>> user.firstName
    u'Zen'
>>> user.lastName
     u'coder'
>>> user.address
     <user_address.Address at 0x1035b4710>
>>> user.address.addressFirstLine
    u'High st, Point place'
>>> user.address.city
    u'Wisconcin'
>>> user.address.pincode
    u'4E23C'

此实现还支持具有地址参数列表而不是字典。如果传递了不受支持的类型，它也会引发描述性错误。

>>> user_dict = json.loads('{
    "firstName" : "Zen", "lastName" : "coder", 
    "address" : ["High st, Point place", "Wisconcin", "4E23C"]
    }')
>>> user = User(**user_dict)
>>> user.address
    <user_address.Address at 0x10ced2d10>
>>> user.address.city
    u'Wisconcin'
>>> user_dict = json.loads('{
    "firstName" : "Zen", "lastName" : "coder", 
    "address" : "bad address"
    }')
    TypeError: address must be provided as an Address object, list, or dictionary

另一个答案还讨论了使用更抽象的方法将Python dict转换为Python对象：Convert Python dict to object

如何将Java中生成的序列化JSON转换为Python中的复杂对象？

1 个答案: