Question

我需要从url中提取后缀，意思是：

http://google.com/sports/golf =＆gt;运动/高尔夫 http://yahoo.com/blog?id=7 =＆gt;博客/ ID = 7

我怎样才能用正则表达式（ruby风格）来实现它？

谢谢

Answer 1

将URI模块与.path + .query一起使用。

uri = URI("http://google.com/sports/golf")
uri.path + "/" + uri.query

Answer 2

以下如何：:)）

require 'uri'
p URI.split("http://google.com/sports/golf").compact.drop(2).join("/")
p URI.split("http://yahoo.com/blog?id=7").compact.drop(2).join("/")

或者，

require 'uri'

a = ["http://google.com/sports/golf","http://stackoverflow.com/questions/15766337/extract-suffix-from-url-regex/15766456#15766456","http://yahoo.com/blog?id=7"]
a.each { |url| p URI.split(url).compact.drop(2).join("/") }

输出：

"/sports/golf"
"/questions/15766337/extract-suffix-from-url-regex/15766456/15766456"
"/blog/id=7"

Answer 3

试试这个：

irb(main):011:0> /(?:http:\/\/\w+\.\w+\/)(.+)/.match("http://yahoo.com/blog?id=7")[1]
=> "blog?id=7"
irb(main):012:0> /(?:http:\/\/\w+\.\w+\/)(.+)/.match("http://google.com/sports/golf")[1]
=> "sports/golf"
irb(main):013:0>

从url（regex）中提取后缀

3 个答案: