我是功能级别情节的新手。 Ich有x,y,z,我想通过以下方式可视化水平图:
> require(lattice)
> head(z)
[,1] [,2] [,3] [,4] [,5] [,6] [,7] [,8] [,9]
[1,] 4.5 4.7 4.6 4.6 4.6 4.6 4.6 4.6 4.7
[2,] 4.5 4.6 4.6 4.6 4.6 4.6 4.6 4.6 4.7
[3,] 4.5 4.7 4.6 4.6 4.6 4.6 4.7 4.6 4.7
[4,] 4.5 4.6 4.6 4.6 4.6 4.6 4.6 4.6 4.7
[5,] 4.6 4.6 4.6 4.6 4.6 4.6 4.6 4.6 4.7
[6,] 4.5 4.7 4.6 4.6 4.6 4.6 4.6 4.6 4.7
> head(y)
[,1]
[1,] 1
[2,] 2
[3,] 3
[4,] 5
[5,] 7
[6,] 10
> head(x)
[1] "2013-01-03 04:30:00 GMT" "2013-01-03 04:45:00 GMT" "2013-01-03 05:00:00 GMT"
[4] "2013-01-03 05:15:00 GMT" "2013-01-03 05:30:00 GMT" "2013-01-03 05:45:00 GMT"
z代表水温和y水深
我想以下列方式绘制数据:
> levelplot(z~x*y)
正确绘制了轴和图例,但根本没有绘制内容。任何人都可以帮助我吗?
祝你好运, 菲利普
答案 0 :(得分:3)
虽然我不知道您为什么尝试不起作用,但似乎使用levelplot.array
代替levelplot.formula
正常工作(指定了aspect="fill"
):
x <- as.POSIXct(x) #make sure x are POSIXct and not just characters
levelplot(z, row.values=x, column.values=y, aspect="fill")