Question

我有2个像这样的SQL查询

SELECT TOP 100 PERCENT 
   COUNT(kodeall) AS Total, kodeall, kode, LEFT(kodeall, 1) AS kode1
FROM
   dbo.data 
WHERE 
   date BETWEEN '2013/03/01 00:00:00' AND '2013/03/01 23:59:00'
   AND (kodeall IS NOT NULL)
GROUP BY 
   kodeall, kode 
ORDER BY 
   kode1

和结果

Total  l kodeall l kode l kode1 
2        1a         AA     1     
5        1d         BB     1           
2        2a         CC     2           
6        2d         DD     2           
1        2e         EE     2           
3        3a         FF     3           
2        3c         GG     3           
1        3f         WW     3

查询＃2：

SELECT     
    COUNT(kodeall) AS Sum, LEFT(kodeall, 1) AS kode1
From 
    dbo.data 
WHERE 
     date BETWEEN '2013/03/01 00:00:00' 
     AND '2013/03/01 23:59:00' 
     AND (kodeall IS NOT NULL)
GROUP BY 
     LEFT(kodeall, 1)

和结果

Sum l kode1 l 
 7      1     
 9      2     
 6      3

如果我想要显示这样的结果

Total  l kodeall l kode l kode1 l sum l Percentage
2        1a         AA     1       7     28.57 %
5        1d         BB     1       7     71.43 %
2        2a         CC     2       9     22.22 %
6        2d         DD     2       9     66.66 %
1        2e         EE     2       9     11.11 %
3        3a         FF     3       6     50 %
2        3c         GG     3       6     33.33 %
1        3f         WW     3       6     16.67 %

sum是在查询A中用kode1计算kodeall。

和百分比=总数/总和* 100 例2/7 * 100

请帮帮我

Answer 1

  SELECT TOP 100 PERCENT 
    COUNT(kodeall) AS Total,
kodeall, kode, 
LEFT(kodeall, 1) AS kode1 ,
    sum1,
    ((Count(kodeall)/sum1 )* 100) As percentage
FROM
   dbo.data 
INNER JOIN 
 (SELECT     
    COUNT(kodeall) AS Sum, 
LEFT(kodeall, 1) AS kode1
    From 
    dbo.data 
   WHERE 
      date BETWEEN '2013/03/01 00:00:00' 
      AND '2013/03/01 23:59:00' 
      AND (kodeall IS NOT NULL)
   GROUP BY 
     LEFT(kodeall, 1)  
  ) temp on temp.kode1 = dbo.data.kode1 

WHERE 
   date BETWEEN '2013/03/01 00:00:00' AND '2013/03/01 23:59:00'
   AND (kodeall IS NOT NULL)
   GROUP BY 
   kodeall, kode 
 ORDER BY 
   dbo.data.kode1

Answer 2

这应该非常接近（未经测试）

With cte1 as (
    SELECT COUNT(kodeall) AS Total, kodeall, kode, LEFT(kodeall, 1) AS kode1
    FROM dbo.data 
    WHERE date >= '2013/03/01' AND  date < '2013/03/02'
       AND kodeall IS NOT NULL
    GROUP BY kodeall, kode 
), cte2 as (
    SELECT COUNT(kodeall) AS Sum, LEFT(kodeall, 1) AS kode1
    From dbo.data 
    WHERE date >= '2013/03/01' AND  date < '2013/03/02'
       AND kodeall IS NOT NULL
    GROUP BY LEFT(kodeall, 1)
)
SELECT c1.Total, c1.kodeall, c1.kode, c1.kode1, 
    c2.sum, c1.Total/c2.sum percentage
FROM cte1 c1 
    JOIN cte2 c2 ON c1.kode1 = c2.kode1

小心使用BETWEEN，尤其是日期字段。相反，我会使用大于或小于。

Answer 3

我认为自己已经非常接近回答了。我以SQL Server作为RDBMS为例。你没有在你的问题中提到RDBMS。
我使用两个CTE（公用表表达式）来保存您的两个查询，然后将它们连接在一起并计算百分比，请注意，您在最终结果中的百分比实际上是一个字符串。


;WITH CTE_TotalKodeall
AS 
(
    SELECT TOP 100 PERCENT 
       COUNT(kodeall) AS Total, kodeall, kode, LEFT(kodeall, 1) AS kode1
    FROM
       dbo.data 
    WHERE 
       date BETWEEN '2013/03/01 00:00:00' AND '2013/03/01 23:59:00'
       AND (kodeall IS NOT NULL)
    GROUP BY 
       kodeall, kode 
    ORDER BY 
       kode1
), CTE_SUMKodeall
AS 
(
   SELECT     
    COUNT(kodeall) AS [Sum], LEFT(kodeall, 1) AS kode1
   From 
    dbo.data 
   WHERE 
     date BETWEEN '2013/03/01 00:00:00' 
     AND '2013/03/01 23:59:00' 
     AND (kodeall IS NOT NULL)
   GROUP BY 
     LEFT(kodeall, 1)  
)
SELECT A.Total, A.kodeall, A.kode, A.kode1, B.[sum], 
       LEFT(cast((A.Total/(B.[SUM]*1.0) *100.0) as varchar(30)),5)+'%' as Percentage
FROM CTE_TotalKodeall A 
JOIN CTE_SUMKodeall B
ON A.kode1 = B.kode1

显示2个查询的结果

3 个答案: