Question

以下是我的XML文件示例：

<?xml version="1.0" encoding="utf-8"?>
<assurances>
<assurance hasReference="true">
    <message>You're Awesome!</message>
    <reference>Genesis 1:26</reference>
</assurance>
<assurance hasReference="true">
    <message>Your Wonderfull!</message>
    <reference>Genesis 1:26</reference>
</assurance>
</assurances>

我正在使用这样的代码来尝试检索它：

int eventType = -1;
    while(eventType != XmlResourceParser.END_DOCUMENT)
    {
        XmlResourceParser assurances = getResources().getXml(R.xml.assurances); 
        String name = assurances.getText();
        Log.d(TAG, name);

        try {
            if (assurances.getEventType() == XmlResourceParser.START_TAG) {
                String s = assurances.getName();

                if (s.equals("assurance")) {
                    String strMessage = assurances.getAttributeValue(null, "message");
                    String strReference = assurances.getAttributeValue(null, "reference");

                    Log.d(TAG, strMessage);
                    Log.d(TAG, strReference);
                }
            }
        } catch (XmlPullParserException e) {
            // TODO Auto-generated catch block
            e.printStackTrace();
        }
    }

它没有得到数据，我不知道从哪里开始。

Answer 1

您不需要使用getAttributeValue方法，而是需要使用getText（）方法。我已对您的代码进行了一些更改，因此如果您使用下面的代码，那么它将正常工作：

int eventType = -1;
while(eventType != XmlResourceParser.END_DOCUMENT)
{
    XmlResourceParser assurances = getResources().getXml(R.xml.assurances); 
    String name = assurances.getText();
    Log.d(TAG, name);

    try {
        if (assurances.getEventType() == XmlResourceParser.START_TAG) {
            String s = assurances.getName();

            if (s.equals("assurance")) {
                assurances.next();   /// moving to the next node
                if(assurances.getName() != null && assurances.getName().equalsIgnoreCase("message")){
                    String strMessage = assurances.getText();  ///to get value getText() method should be used
                    assurances.next();   ///jumping on to the next node
                String strReference = assurances.getText();  ////similar to above
            }

                Log.d(TAG, strMessage);
                Log.d(TAG, strReference);
            }
        }
    } catch (XmlPullParserException e) {
        // TODO Auto-generated catch block
        e.printStackTrace();
    }
}

Answer 2

希望这会对你有所帮助。问候小号

public static void main(String[] args) {
    try {
        DocumentBuilderFactory dbf = DocumentBuilderFactory.newInstance();
        DocumentBuilder db = dbf.newDocumentBuilder();
        Document doc = db.parse(new File("c:\\_work\\test.xml"));

        //get nodes by name
        NodeList nl = doc.getElementsByTagName("assurance");
        int nbrOfElements = nl.getLength();
        for (int i = 0; i < nbrOfElements; i++) {
            Element e = (Element) nl.item(i);
            System.out.print(e.getTagName());
            System.out.print(":");
            System.out.println(e.getTextContent());
        }
    } catch (Exception ex) {
        Logger.getLogger(Main.class.getName()).log(Level.SEVERE, null, ex);
    }
}

XMLResourceParser，我不知道如何阅读我拥有的XML

2 个答案: