Question

我正在尝试在phpseclib中使用RSA实现，我认为在函数中执行一次代码会更容易并重新使用该函数。当我尝试发短信代码时，我收到一条错误，说“解密错误” 测试还让我意识到每次代码运行时密文都不同，所以我显然在那里做错了！

这些功能的代码是：

require_once "Crypt/RSA.php";
require_once "Crypt/AES.php";

//Function for encrypting with RSA
function rsa_encrypt($string, $public_key)
{
    //Create an instance of the RSA cypher and load the key into it
    $cipher = new Crypt_RSA();
    $cipher->loadKey($public_key);
    //Set the encryption mode
    $cipher->setEncryptionMode(CRYPT_RSA_ENCRYPTION_PKCS1);
    //Return the encrypted version
    return base64_encode($cipher->encrypt($string));
}

//Function for decrypting with RSA 
function rsa_decrypt($string, $private_key)
{
    //Create an instance of the RSA cypher and load the key into it
    $cipher = new Crypt_RSA();
    $cipher->loadKey($private_key);
    //Set the encryption mode
    $cipher->setEncryptionMode(CRYPT_RSA_ENCRYPTION_PKCS1);
    //Return the decrypted version
    return $cipher->decrypt($string);
}

我尝试使用以下方法测试它：（这些键仅用于测试，因此它的硬编码就是为什么）。在这里，每次运行代码时，$ ciphertext的值每次都会改变

//Private key
$private_key = "-----BEGIN RSA PRIVATE KEY----- MIICXAIBAAKBgQCU+1bLfPmcY7qrF/dTbAtuJlv4R/FVc1WEH9HKU0jQjX/n/db9vz/x0i3te/bK LNEcwUhBu+PWPnOt/qVURG9BUT6RsCRFUn0CyGiUKoy45o9K/mJAHmbrNtrUB6ckrYLF75Y50nUN sBVHUDw8yQymmiOBT1gc/KM5s1xTz44LMwIDAQABAoGAGsiMtAyFu23ac0PdvOuhqm3O/vXAF0Ki zxwBVURfxM6LfiOOcRPe5RSKGTW+Cl7AQVEmMlsa/LtBhLhQ9LNQ5L/4oTmRhCGiZZEmccAdjKsx yMeaxkp+ZHvMxMKQNDgYg1CXqrCrpwwUuMUlA26tfxZ3xSFtFyDTaV9mgDQ1IGECQQCkX9Tum7D1 vQTwbhbYnu7eC4eUOaZeGWSEs2csK7U6vfZ3BzUZW/0tPqcSpQqcNxMtY9TiUsNRj1uM6jX3byp7 AkEA6Ab+wvOTNRtES77OAYG9gHGZZ+iXjQJ/6Z7JehN4p41UbDIf9nNUOLUPL9z5V1uOYnl1CWoo Cw95cdhKXxEAqQJBAIU5Or6tp250ZdVslM27ewSyuY9UblfkIsk/EscFIdzbbDAqwkmsefW6yvTc mU3lgYCPYlKRG8c19tCuX1ENY5MCQAz37x9YW975Ai01ofAFn2DheJCNOINCI4IcROiU1AaRaKmP d6fftFJjFFE5iZovXNr2LOt0yn4rxD7vtuBvY9kCQGyty6YCB6qaD7qXPMhLrLbGajAIWd6ETgxv frK/BJu+buPfDky/g1FhI5R9iMtL1xH0JYLJlaVocU+xSeA9DkY= -----END RSA PRIVATE KEY-----";
//Public key
$public_key = "-----BEGIN PUBLIC KEY----- MIGfMA0GCSqGSIb3DQEBAQUAA4GNADCBiQKBgQCU+1bLfPmcY7qrF/dTbAtuJlv4R/FVc1WEH9HK U0jQjX/n/db9vz/x0i3te/bKLNEcwUhBu+PWPnOt/qVURG9BUT6RsCRFUn0CyGiUKoy45o9K/mJA HmbrNtrUB6ckrYLF75Y50nUNsBVHUDw8yQymmiOBT1gc/KM5s1xTz44LMwIDAQAB -----END PUBLIC KEY-----";


//Test out the rsa encryption functions
$plaintext = "This is some plaintext to encrypt";
$ciphertext = rsa_encrypt($plaintext, $public_key);
$decipheredtext = rsa_decrypt($ciphertext, $private_key);

//Echo out results
echo sprintf("<h4>Plaintext for RSA encryption:</h4><p>%s</p><h4>After encryption:</h4><p>%s</p><h4>After decryption:</h4><p>%s</p>", $plaintext, $ciphertext, $decipheredtext);

修改示例输出为：

用于RSA加密的明文：

这是我们将加密的一些明文

加密后：

'〜_æž|WýF|E×9安培;！美国'jéÓb÷AAS€É7J+Ûªß¯×ZEA©ë£＃（÷）AX“）÷O'Ë±N个@ OV«ÓÌPƒ¹-AI ！一个¢|a＆安培;Á½Á~ö‰ºŠCðJ«VW {uAåoOÂXäÞ＃÷ï`agÏ：OOE

解密后：

//没有返回任何内容，此处为空白

Answer 1

我认为GigaWatt的答案是正确的。至于：

测试也让我意识到密文各有不同代码运行的时间，所以我显然在那里做错了什么！

PKCS＃1填充添加随机字节，因此密文将始终不同。然而，PKCS＃1算法知道明文何时结束并且随机字节开始，因此它能够将两者分开并返回您想要的结果。

编辑：我用新线替换了键中的空格后，我开始工作了。例如

$private_key = "-----BEGIN RSA PRIVATE KEY-----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-----END RSA PRIVATE KEY-----";
//Public key
$public_key = "-----BEGIN PUBLIC KEY-----
MIGfMA0GCSqGSIb3DQEBAQUAA4GNADCBiQKBgQCU+1bLfPmcY7qrF/dTbAtuJlv4R/FVc1WEH9HK
U0jQjX/n/db9vz/x0i3te/bKLNEcwUhBu+PWPnOt/qVURG9BUT6RsCRFUn0CyGiUKoy45o9K/mJA
HmbrNtrUB6ckrYLF75Y50nUNsBVHUDw8yQymmiOBT1gc/KM5s1xTz44LMwIDAQAB
-----END PUBLIC KEY-----";

在PHP中使用phpseclib的RSA问题

1 个答案: