Question

我有一个包含如下行

的表格

ID  User      Department
1   User1     Admin
2   User1     Accounts
3   User2     Finance
4   User3     Sales
5   User3     Finance

我需要一个选择查询，其格式为

ID  User      Department
1   User1     Admin,Accounts
2   User2     Finance
3   User3     Sales, Finance

Answer 1

您使用sql-server和plsql标记了问题，因此我将为SQL Server和Oracle提供答案。

在SQL Server中，您可以使用FOR XML PATH将多行连接在一起：

select distinct t.[user],
  STUFF((SELECT distinct ', ' + t1.department
         from yourtable t1
         where t.[user] = t1.[user]
            FOR XML PATH(''), TYPE
            ).value('.', 'NVARCHAR(MAX)') 
        ,1,2,'') department
from yourtable t;

请参阅SQL Fiddle with Demo。

在Oracle 11g +中，您可以使用LISTAGG：

select "User",
  listagg(department, ',') within group (order by "User") as departments
from yourtable
group by "User"

请参阅SQL Fiddle with Demo

在Oracle 11g之前，您可以使用wm_concat函数：

select "User",
  wm_concat(department) departments
from yourtable
group by "User"

Answer 2

在Sql Server中，您可以使用它。

DECLARE @UserMaster TABLE( 

    UserID INT NOT NULL, 

    UserName varchar(30) NOT NULL 

); 

INSERT INTO @UserMaster VALUES (1,'Rakesh')

INSERT INTO @UserMaster VALUES (2,'Ashish')

INSERT INTO @UserMaster VALUES (3,'Sagar')

SELECT * FROM @UserMaster

DECLARE @CSV VARCHAR(MAX) 

SELECT @CSV = COALESCE(@CSV + ', ', '') + UserName from @UserMaster 

SELECT @CSV AS Result

Answer 3

MYSQL：要将列值作为逗号分隔值使用GROUP_CONCAT( )函数作为

GROUP_CONCAT(  `column_name` )

例如

SELECT GROUP_CONCAT(  `column_name` ) 
FROM  `table_name` 
WHERE 1 
LIMIT 0 , 30

Answer 4

您可以使用以下SQL执行此操作：

SELECT STUFF
(
    (
        SELECT ',' + s.FirstName 
        FROM Employee s
        ORDER BY s.FirstName FOR XML PATH('')
    ),
     1, 1, ''
) AS Employees

Answer 5

对于Mysql：

SELECT t.user, 

(SELECT GROUP_CONCAT( t1.department ) FROM table_name t1 WHERE t1.user = t.user)department

FROM table_name t
GROUP BY t.user
LIMIT 0 , 30

Answer 6

SELECT name, GROUP_CONCAT( section ) 
FROM  `tmp` 
GROUP BY name

Answer 7

I think it will be easy to you. I am using group_concat which concatenate diffent values with separator as we have defined

select ID,User, GROUP_CONCAT(Distinct Department order  by Department asc 

separator ', ') as Department from Table_Name   group by ID

Answer 8

尝试以下查询：

select distinct Users,
 STUFF(
        (
        select ', ' + d.Department FROM @temp d
        where t.Users=d.Users
group by d.Department for xml path('')
        ), 1, 2, '') as Departments
 from @temp t

实现：

Declare @temp Table(
ID int,
Users varchar(50),
Department varchar(50)
)
insert into @temp
(ID,Users,Department)
values
(1,'User1','Admin')
insert into @temp
(ID,Users,Department)
values
(2,'User1','Accounts')
insert into @temp
(ID,Users,Department)
values
(3,'User2','Finance')
insert into @temp
(ID,Users,Department)
values
(4,'User3','Sales')
insert into @temp
(ID,Users,Department)
values
(5,'User3','Finance')

 select distinct Users,
 STUFF(
        (
        select ', ' + d.Department FROM @temp d
        where t.Users=d.Users
group by d.Department for xml path('')
        ), 1, 2, '') as Departments

 from @temp t

结果将是：

Answer 9

对于不支持WM_CONCAT的Oracle版本，可以使用以下内容

  select "User", RTRIM(
     XMLAGG (XMLELEMENT(e, department||',') ORDER BY department).EXTRACT('//text()') , ','
     ) AS departments 
  from yourtable 
  group by "User"

这个功能更加强大和灵活 - 您可以在 listagg 中指定每个组中的分隔符和排序顺序。

如何以逗号分隔值获取列值

9 个答案:

实现：

结果将是：