Question

我有一个使用jaxb和spring webservice构建的java Web服务应用程序。

我在xsd中有一个复杂的类型：

...

<complexType name="GetRecordsRequest">
    <sequence>
        <element name="maxRecords" type="int" maxOccurs="1" minOccurs="1"/>
    </sequence>
</complexType>

...

使用 xjc ，我有从xsd生成的jaxb类：

public class GetRecordsRequest {
    protected int maxRecords;

    public int getMaxRecords() {
        return maxRecords;
    }

    public void setMaxRecords(int value) {
        this.maxRecords = value;
    }
}

我在spring context.xml中使用了 PayloadValidatingInterceptor 来确保用户不能为maxRecords输入除整数之外的任何内容：

<bean class="org.springframework.ws.server.endpoint.mapping.PayloadRootAnnotationMethodEndpointMapping">
    <property name="interceptors">
        <list>
            <ref local="validatingInterceptor" />
        </list>
    </property>
</bean>

<bean id="validatingInterceptor" class="org.springframework.ws.soap.server.endpoint.interceptor.PayloadValidatingInterceptor">
    <property name="schema" value="/WEB-INF/schemas/webservice.xsd" />
    <property name="validateRequest" value="true" />
    <property name="validateResponse" value="true" />
</bean>

当我在Soap UI中输入此soap请求xml时：

<soapenv:Envelope xmlns:soapenv="http://schemas.xmlsoap.org/soap/envelope/" xmlns:ns1="http://www.test.com/ns1">
   <soapenv:Header/>
   <soapenv:Body>
      <ns1:GetRecordsRequest>
         <ns1:maxRecords></ns1:maxRecords>
      </ns1:GetRecordsRequest>
   </soapenv:Body>
</soapenv:Envelope>

我得到的回复信息是：

<SOAP-ENV:Envelope xmlns:SOAP-ENV="http://schemas.xmlsoap.org/soap/envelope/">
   <SOAP-ENV:Header/>
   <SOAP-ENV:Body>
      <SOAP-ENV:Fault>
         <faultcode>SOAP-ENV:Client</faultcode>
         <faultstring xml:lang="en">Validation error</faultstring>
         <detail>
            <spring-ws:ValidationError xmlns:spring-ws="http://springframework.org/spring-ws">cvc-datatype-valid.1.2.1: '' is not a valid value for 'integer'.</spring-ws:ValidationError>
            <spring-ws:ValidationError xmlns:spring-ws="http://springframework.org/spring-ws">cvc-type.3.1.3: The value '' of element 'cis:maxRecords' is not valid.</spring-ws:ValidationError>
         </detail>
      </SOAP-ENV:Fault>
   </SOAP-ENV:Body>
</SOAP-ENV:Envelope>

你可以看到结果只是一个字段的两行神秘消息。我只需要一行就可以使响应消息更漂亮吗？有没有办法自定义验证错误响应消息？

Answer 1

您可以使用AbstractValidatingInterceptor的方法自定义验证错误响应（PayloadValidatingInterceptor是此抽象类的实现），即：

setDetailElementName（QName detailElementName）
setFaultStringOrReason（String faultStringOrReason）

部分示例：

public final class MyPayloadValidatingInterceptor
extends PayloadValidatingInterceptor {

    @Override
    protected Source getValidationRequestSource(WebServiceMessage webSerMessage_) {
        _source = webSerMessage_.getPayloadSource();
        validateSchema(_source);
        return _source;
    }

    private void validateSchema(Source source_) throws Exception {
        SchemaFactory _schemaFactory = SchemaFactory.newInstance(XMLConstants.W3C_XML_SCHEMA_NS_URI);
        Schema _schema = _schemaFactory.newSchema(getSchemas()[0].getFile());

        Validator _validator = _schema.newValidator();
        DOMResult _result = new DOMResult();
        try {
            _validator.validate(source_, _result);
        } catch (SAXException _exception) {
            // modify your soapfault here                
        }
    }
}

Answer 2

您可以通过扩展PayloadValidatingInterceptor并覆盖handleRequestValidationErrors来自定义验证错误消息。我们可以在messageContext的主体中设置自定义错误消息。

1）您可以返回带有验证错误消息的自定义xml响应，而不是请求验证错误的SOAP Fault。

2）SAXParseException []错误包含请求验证错误。您可以选择仅返回一个错误作为响应。（或）对于某些预定义错误，您可以返回自定义错误消息，而不是SAXParseException中返回的错误消息。

/**
* The Class CustomValidatingInterceptor.
*/
public class CustomValidatingInterceptor extends PayloadValidatingInterceptor{

/* (non-Javadoc)
 * @see org.springframework.ws.soap.server.endpoint.interceptor.AbstractFaultCreatingValidatingInterceptor#handleRequestValidationErrors(org.springframework.ws.context.MessageContext, org.xml.sax.SAXParseException[])
 */
@Override
protected boolean handleRequestValidationErrors(MessageContext messageContext, SAXParseException[] errors) throws TransformerException {
    JAXBContext jaxbContext;
    StringWriter stringWriter = new StringWriter();
    ResponseTransactionDetail transactionDetail = null;

    for (SAXParseException error : errors) {
        logger.debug("XML validation error on request: " + error.getMessage());
    }
    if (messageContext.getResponse() instanceof SoapMessage) {

        /**
         * Get SOAP response body in message context (SOAP Fault)
         */

        SaajSoapMessage soapMessage = (SaajSoapMessage)messageContext.getResponse();
        SoapBody body = soapMessage.getSoapBody();

        // marshal custom error response to stringWriter

        /**
        * Transform body
        */
        Source source = new StreamSource(new StringReader(stringWriter.toString()));
        identityTransform.transform(source, body.getPayloadResult());
        stringWriter.close();
    }
    return false;
}

如何自定义spring webservice的PayloadValidatingInterceptor响应消息？

2 个答案: