Question

假设我有以下变量：

suits = ["h","c", "d", "s"]
cards = ["2","3", "4", "5", "6", "7", "8", "9", "t", "j", "q", "k", "a"]
deck = []

for suit in suits:
    for card in cards:
        deck.append(str(card+suit))

我想编写一个函数，给定一张特定的卡片，可以生成对的可能组合。

例如，generatePairs('a')应返回类似：

的内容

['ahac','ahad','ahas','acad','acas','adas']

但我不确定如何写这个功能。

Answer 1

In [7]: import itertools

In [8]: c = 'a'

In [9]: ['%s%s%s%s' % (c, s1, c, s2) for (s1, s2) in itertools.combinations(suits, 2)]
Out[9]: ['ahac', 'ahad', 'ahas', 'acad', 'acas', 'adas']

Answer 2

你需要像

这样的东西

In [5]: deck = []

In [6]: for i in itertools.combinations(suits, 2):
   ...:     for j in cards:
   ...:         deck.append(j+i[0]+j+i[1])
   ...:

In [7]: print deck
['2h2c', '3h3c', '4h4c', '5h5c', '6h6c', '7h7c', '8h8c', '9h9c', 'thtc', 'jhjc', 'qhqc', 'khkc', 'ahac',
', '3h3d', '4h4d', '5h5d', '6h6d', '7h7d', '8h8d', '9h9d', 'thtd', 'jhjd', 'qhqd', 'khkd', 'ahad', '2h2s'
3s', '4h4s', '5h5s', '6h6s', '7h7s', '8h8s', '9h9s', 'thts', 'jhjs', 'qhqs', 'khks', 'ahas', '2c2d', '3c3
4c4d', '5c5d', '6c6d', '7c7d', '8c8d', '9c9d', 'tctd', 'jcjd', 'qcqd', 'kckd', 'acad', '2c2s', '3c3s', '4
 '5c5s', '6c6s', '7c7s', '8c8s', '9c9s', 'tcts', 'jcjs', 'qcqs', 'kcks', 'acas', '2d2s', '3d3s', '4d4s',
', '6d6s', '7d7s', '8d8s', '9d9s', 'tdts', 'jdjs', 'qdqs', 'kdks', 'adas']

python：如何在一副牌中生成一对牌

2 个答案: