Question

我有点卡在这里..基本上我试图获取用户的邮政编码位置。我有从GPS坐标获取ZIP的代码，但我似乎无法得到任何坐标。这是我到目前为止的代码 -

Log.d(TAG, "Zip is going to be autoset");
new Thread() {
    public void run() {
        LocationManager locationManager;
        String provider;
        // Get the location manager
        locationManager = (LocationManager) getSystemService(Context.LOCATION_SERVICE);
        // Define the criteria how to select the locatioin provider -> use
        // default
        LocationListener locListener = new LocationListener() {
            @Override
            public void onStatusChanged(String provider, int status, Bundle extras) {
            }
            @Override
            public void onProviderEnabled(String provider) {
            }
            @Override
            public void onProviderDisabled(String provider) {
            }
            @Override
            public void onLocationChanged(Location location) {
            }
        };

        locationManager.requestLocationUpdates(LocationManager.NETWORK_PROVIDER, 0, 0, locListener);
        Criteria criteria = new Criteria();
        criteria.setAccuracy(Criteria.ACCURACY_COARSE);
        criteria.setAltitudeRequired(false);//true if required
        criteria.setBearingRequired(false);//true if required
        criteria.setCostAllowed(false);
        criteria.setPowerRequirement(Criteria.POWER_LOW);
        provider = locationManager.getBestProvider(criteria, true);//search for enabled provider
        //locationManager.requestSingleUpdate(criteria, locListener, null);
        Location location= locationManager.getLastKnownLocation(provider);
        Log.d(TAG,"Lat - " + (location.getLatitude()) + " long - " + (location.getLongitude()));
        latitude = (location.getLatitude());
        longitude = (location.getLongitude());
        Log.d(TAG, "Passing this link https://maps.googleapis.com/maps/api/geocode/xml?latlng="+latitude+","+longitude+"&sensor=true");
        locationManager.removeUpdates(locListener);
        try {
        //Log.d(TAG, "Trying to access "+ "https://maps.googleapis.com/maps/api/geocode/xml?latlng="+location.getLatitude()+","+location.getLongitude()+"&sensor=true"
            //Log.d(TAG, "Trying to access "+ "https://maps.googleapis.com/maps/api/geocode/xml?latlng=40.714224,-73.961452&sensor=true");
            URL url = new URL("https://maps.googleapis.com/maps/api/geocode/xml?latlng="+latitude+","+longitude+"&sensor=true");
            InputStream stream = url.openStream();
            BufferedInputStream buf = new BufferedInputStream(stream);
            StringBuilder sb = new StringBuilder();
            while (true){
                int data = buf.read();
                if (data==-1){
                    break;
                }else{
                    sb.append((char)data);
                }
            }
            int zipEnd = sb.indexOf("</short_name><type>postal_code");
            Log.d(TAG,"ZIP is "+sb.substring(zipEnd-6, zipEnd));
            ZipCode = Integer.parseInt(sb.substring(zipEnd-6, zipEnd));
        } catch (MalformedURLException e) {
            e.printStackTrace();
        } catch (IOException e) {
            e.printStackTrace();
        }
    }
}.run();

我遇到的最新错误说我无法在未调用looper.prepare的线程中创建一个处理程序。

我只需要一个粗略的位置更新（网络位置将是完美的）所以我可以从中获取邮政编码。

谢谢。

Answer 1

使用Geocoder

创建地址列表，然后使用getPostalCode()

Answer 2

而不是new Thread()更改为新Thread(new Runnable()

new Thread(new Runnable()
{   

    @Override
    public void run()
    {
        Looper.prepare();

        // The rest of your code in between 
        // LocationManager locationManager;
        // and 
        // catch (IOException e) {
        // e.printStackTrace();
        // }

        Looper.loop();
    }
}).start();

Android - 从网络获取一次位置

2 个答案: