有没有办法从OWL本体文件中获取基本命名空间,而不使用DOM或类似的东西,只是使用Jena的API?例如,来自OWL文件:
<rdf:RDF
xmlns:rdf="http://www.w3.org/1999/02/22-rdf-syntax-ns#"
xmlns:protege="http://protege.stanford.edu/plugins/owl/protege#"
xmlns="http://www.owl-ontologies.com/Ontology1254827934.owl#"
xmlns:xsp="http://www.owl-ontologies.com/2005/08/07/xsp.owl#"
xmlns:owl="http://www.w3.org/2002/07/owl#"
xmlns:xsd="http://www.w3.org/2001/XMLSchema#"
xmlns:swrl="http://www.w3.org/2003/11/swrl#"
xmlns:swrlb="http://www.w3.org/2003/11/swrlb#"
xmlns:rdfs="http://www.w3.org/2000/01/rdf-schema#"
xml:base="http://www.owl-ontologies.com/Ontology1254827934.owl">
如何在运行时获得http://www.owl-ontologies.com/Ontology1254827934.owl
?
答案 0 :(得分:3)
一种方式:
//Create the Ontology Model
OntModel model = ModelFactory.createOntologyModel();
//Read the ontology file
model.begin();
InputStream in = FileManager.get().open(FILENAME_HERE);
if (in == null) {
throw new IllegalArgumentException("File: " + filename + " not found");
}
model.read(in,"");
model.commit();
//Get the base namespace
model.getNsPrefixURI("");
答案 1 :(得分:3)
或者,如果你真的想要xml:base而不是空的xmlns:
final ArrayList<String> baseUriDropHere = new ArrayList<>();
DefaultHandler handler = new DefaultHandler() {
@Override
public void startElement(String uri, String localName, String qName, Attributes attributes) throws SAXException {
if("rdf:RDF".equals(qName)) {
for (int i=0; i<attributes.getLength(); i++) {
if("xml:base".equals(attributes.getQName(i))) {
baseUriDropHere.add(attributes.getValue(i));
return;
}
}
}
}
};
try {
SAXParserFactory factory = SAXParserFactory.newInstance();
factory.setValidating(false);
SAXParser parser = factory.newSAXParser();
parser.parse(FILENAME_HERE, handler);
} catch (ParserConfigurationException e) {
} catch (SAXException e) {
} catch (IOException e) {
}
if(baseUriDropHere.isEmpty()) {
System.out.println("no base uri set");
} else {
System.out.println(baseUriDropHere.get(0));
}