所以在这段代码中,在" Run"在方法" run"中,扫描仪似乎不想从第一次尝试中获取输入,只在第二行输入输入。我说第二行是因为我输入了输入然后按两次返回,然后在第三行输入输入,它读取第二行,在这种情况下就没有了。
我尝试过BufferedReader的结果相同,所以我相信我正在做一些愚蠢的事情而忽视了一些事情。
import java.util.Scanner;
import java.util.ArrayList;
import java.util.Timer;
import java.util.TimerTask;
import java.io.*;
class Global {
public static int stop = -1;
}
public class DataSort {
public static void main(String[] args){
Timer timer = new Timer();
Direct swit = new Direct();
Run mprog = new Run();
Help hlp = new Help();
String newline = System.getProperty("line.separator");
BufferedReader in = new BufferedReader(new InputStreamReader(System.in));
Scanner console = new Scanner(System.in);
System.out.println(newline);
System.out.println("Welcome to Data Sort! This Program is designed to sort information about targets discoverd by UAV and place the data in a table." + newline);
System.out.print("For help, press any key. To continue, please wait. ");
timer.schedule(swit, 3000);
try {
Global.stop = in.read();
}
catch(IOException e) {
e.printStackTrace();
}
try {
in.close();
}
catch(IOException e) {
e.printStackTrace();
}
}
}
class Direct extends TimerTask {
public void run() {
Run mprog = new Run();
Help hlp = new Help();
if(Global.stop != -1){
System.out.println("Help");
hlp.run();
}
if(Global.stop == -1) {
System.out.println("Main");
mprog.run();
}
}
}
class Help {
public static void run() {
String newline = System.getProperty("line.separator");
System.out.print(newline);
System.out.println("Entering Help Mode!" + newline);
System.out.println("Entered Help Class");
//String help = console.nextLine();
}
}
class Run {
public static void run() {
/*EnterAll eall = new EnterAll();
EnterCoords ecoords = new EnterCoords();
EnterRelation erelat = new EnterRelation();
EnterColor ecolor = new EnterColor();
EnterShape eshape = new EnterShape();
Coordinates coords = new Coordinates();
Relation relat = new Relation();
Color color = new Color();
Shape shape = new Shape();
List list = new List();
Save save = new Save();
SaveAs saveas = new SaveAs();*/
String newline = System.getProperty("line.separator");
Scanner console = new Scanner(System.in);
System.out.print(newline);
System.out.println("Initializing Main Program." + newline);
System.out.println("************************** MAIN MENU *************************" + newline);
System.out.println("Enter Coords \t Enter Relat \t Enter Color \t Enter Shape"+newline);
System.out.println("Coordinates \t Relation \t Color \t \t Shape" + newline);
System.out.println("Help \t \t List \t \t Save \t \t Save As" + newline);
System.out.println("**************************************************************" + newline);
System.out.print("Enter your selection or type All to enter lines consecutively: ");
String raw = console.nextLine();
System.out.println(raw);
String select = errorCheck(raw);
if (select.equals("All")){
}
if (select.equals("Enter Coords")){
}
if (select.equals("Enter Relat")){
}
if (select.equals("Enter Color")){
}
if (select.equals("Enter Shape")){
}
if (select.equals("Coordinates")){
}
if (select.equals("Relation")){
}
if (select.equals("Color")){
}
if (select.equals("Shape")){
}
if (select.equals("Help")){
}
if (select.equals("List")){
}
if (select.equals("Save")){
}
if (select.equals("Save As")){
}
}
private static String errorCheck(String raw) {
String select = raw;
return select;
}
}
答案 0 :(得分:1)
你的问题在于
public class DataSort {...... Global.stop = in.read(); ......}
因为in.read用于读取整数输入。它不会读取行尾字符。这就是为什么在你输入选择字符串并点击回车后它变得毫无瑕疵。
此致 拉维
答案 1 :(得分:0)
@Sean,这是你的解决方案
在下面注释
public class DataSort
{
.
.
.
//BufferedReader in = new BufferedReader(new InputStreamReader(System.in));
//Scanner console = new Scanner(System.in);
.
.
.
//Global.stop = in.read();
.
.
}
对于Global.stop = in.read(),从相同的输入读缓冲区(可能在同一个类或其他位置)读取并根据需要解析字符串。不要创建另一个输入读缓冲区。
此致 拉维