Question

我正在创建一个执行一些简单数学的小程序，但无法运行它。它只输出“意外的文件结束”。我似乎无法找到错误..？

#!/bin/bash

until [ $second_num -ne 0 ]; do
    echo "Enter number 1:"
    read first_num
    echo "Enter number 2:"
    read second_num
    echo "Cannot divide by 0. Start over."
done

result=0
if [ $first_num -ne 999 && $second_num -ne 999 ]; then
    let result=$((first_num/second_num))
    echo $result    
    echo "Program finished!"
else
    echo "You have exited the program."
    exit 0 
fi  

number=1
while [ $number -lt 100 ]; do
    echo $number
    let number=$(( $number % 5 ))
    echo $number >> sample.txt
done

Answer 1

乍一看，我看到你的剧本有两个问题：

until [ $second_num -ne 0 ]; do

您没有初始化$second_num，因此您尝试将0与0进行比较。
if [ $first_num -ne 999 && $second_num -ne 999 ]; then

&&是conditional execution operator。（单个）方括号内的两个表达式的AND运算符是-a。

Answer 2

我不知道你要做什么，但下面的代码应该可以正常工作而没有任何错误

 #!/bin/bash

until [ $second_num -ne 0 ]; do
    echo "Enter number 1:"
    read first_num
    echo "Enter number 2:"
    read second_num
    echo "Cannot divide by 0. Start over."
done

result=0
if [ "$first_num" -ne "999" -a "$second_num" -ne "999" ];

then
    let result=$(($first_num/$second_num))
    echo $result    
    echo "Program finished!"
else
    echo "You have exited the program."
    exit 0
fi

number=1
while [ $number -lt 100 ]; do
    echo $number
    let number=$(( $number % 5 ))
    echo $number >> sample.txt
done

Answer 3

我在bash版本4下执行并没有问题（没有语法错误），但是一些语义错误，变量second_num未定义和＆amp;＆amp;在if语句中第3行：[：-ne：一元运算符预期输入数字1： 34 输入数字2： 54 不能除以0.重新开始。第12行：[：缺少`]' 你已退出该计划。

再次发送脚本

bash文件中出现意外的eof错误

3 个答案: